Answer:
In full volume it contain 0.12 moles.
Explanation:
Given data:
Total volume= Vt = 2.9 L
Decreased volume= Vd = 1.2 L
Number of moles of air present in decreased volume= n = 0.049 mol
Number of moles of air in total volume= n = ?
Solution:
Formula:
Vt/ Vd = n (in total volume) /n ( decreased volume)
2.9 L / 1.2 L = X / 0.049 mol
2.42 = X / 0.049 mol
X = 2.42 × 0.049
X = 0.12 mol
It would be the controlled variable, which is a baseline to compare your other variables too.
Hope this helps!
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The goal of an element is to obtain a noble gas configuration (obtaining a full valence shell). Therefore, certain elements will either gain or lose electrons in order to obtain this full valence shell. In the case of sodium chloride, it is easy for sodium (having one valence electron) to give up its one electron. Chlorine (having seven valence electrons) wants sodium’s electron because it completes its outer shell and chlorine obtains this noble gas configuration. Ionic bonds always involve a transfer of electrons.
