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Delvig [45]
1 year ago
10

The speed of sound in air is 340 m/s. What is the wavelength of a soundwave that has a frequency of 502 Hz?

Physics
1 answer:
Mama L [17]1 year ago
5 0

The formula for calculating velocity of wave is expressed as

v = fλ

where

v = velocity of the wave

λ = wavelength

f = frequency of the wave

From the information given,

v = 340

f = 502

Substituting these values into the formula, we have

340 = 502λ

Dividing both sides of the equation by 502,

340/502 = 502λ/502

λ = 0.68 m

The wavelength is 0.68 m

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slega [8]

Answer:

a)   v_average = 11 m / s, b)  t = 0.0627 s

, c)    F = 7.37 10⁵ N

, d)   F / W = 35.8

Explanation:

a) truck speed can be found with kinematics

         v² = v₀² - 2 a x

The fine speed zeroes them

           a = v₀² / 2x

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           a = 350.72 m / s²

The average speed is

           v_average = (v + v₀) / 2

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           v_average = 11 m / s

b) The average time

          v = v₀ - a t

          t = v₀ / a

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c) The force can be found with Newton's second law

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             F = 2100 350.72

             F = 7.37 10⁵ N

.d) the ratio of this force to weight

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.e) Several approaches will be made:

- the resistance of air and tires is neglected

- It is despised that the force is not constant in time

- Depreciation of materials deformation during the crash

5 0
3 years ago
In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac
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Answer:

a=0.284\ m/s^2

Explanation:

Given that,

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Final velocity of the spaceship, v = 11 m/s

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We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

So, the acceleration experienced by the occupants of the spaceship is 0.284\ m/s^2.

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Answer:

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