What system ??? There’s no picture
W = m · g · h
h = 28.3 m · sin 45° = 28.3 m · 0.707 = 20 m
g = 9.8 m/s²
W = 75 kg · 9.8 m/s² · 20 m
Answer:
W = 14,700 J = 14.7 kJ
Answer:
F= 12 N
Explanation:
Given that
Work done by student ,W= 60 J
The mass of the box ,m = 3 kg
Length ,x = 5 m
We know that ,The work done by a force a force F is given as
W= F .x
x=Displacement
F=Force
W=Work
Now by putting the values
60 = F x 5
F= 12 N
That is why the magnitude of the force will be 12 N.
PART a)
As we know that weight is product of mass and gravity
so here we have
Part B)
Normal force is counter balanced by weight of the crate
so here we have
N = W = 127.4 N
PART C)
As we know that
F = ma
now we have
m = 13 kg
F = 40 N
now we have
Part D)
Maximum static friction force is given as
here we know that
now we have
PART E)
Since applied force on the block is
F = 12 N
Now since applied force is less than maximum static friction force
So it will not slide
So here friction force will be same as applied force
Static friction = 12 N
PART f)
Kinetic friction force is given as
here we know that
now friction force is
now we have
Part g)
as we know that
F = ma
Answer:
yes because if the speed/K.E. of body increases the friction will also apply more instantly