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Leto [7]
3 years ago
11

What kind of water temperature lowers the dissolved oxygen

Physics
2 answers:
bija089 [108]3 years ago
6 0
<h2>Answer:</h2>

<u>Warm water temperature </u><u>lowers the dissolved oxygen</u>

<h2>Explanation:</h2>

Water temperature is one of the most important characteristics of an aquatic system. It affects the solubility of oxygen to a great extent. The solubility of oxygen decreases as water temperature increases.The reason for this inverse relationship between dissolved oxygen and temperature is that the solubility of a gas in a liquid is an equilibrium phenomenon therefore cold water can hold more dissolved oxygen than warm water.

ehidna [41]3 years ago
5 0
<h3>Answer</h3>

At a high temperature above 20° oxygen solubility starts to decrease.

<h3>Explanation</h3>

Oxygen, O2 is a very essential component of water as we can see in its chemical formula h2O.

The solubility of oxygen decreases as temperature increases. This means that warmer water will have less dissolved oxygen than does cooler water.

<h3>Other factors that affects oxygen solubility in water</h3>

Salt levels

higher the salt levels in water, lower will be oxygen in it.

Pressure

Water at lower altitudes can hold more dissolved oxygen than water at higher altitudes because dissolved oxygen will increase as pressure increases.

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Which change will always result in an increase in the gravitational force between 2 objects
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A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery a
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Answer:

The potential difference between the plates increases

Explanation:

As we know that the capacitance of the capacitor is given by:

q = CV         (1)

where

q = charge

C = capacitance

V = Voltage or Potential Difference

Also, the capacitance of a parallel plate capacitor is given as:

C = \frac{\epsilon_{o}A}{D}           (2)

where

\epsilon_{o} = permittivity of free space or vacuum

A = Area of the plates

D = Separation distance between the plates

Now, from eqn (1) and (2):

V = \frac{qD}{A\epsilon_{o}}

Now, from the above eqn  we can say that:

Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.

Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.

4 0
3 years ago
A particle oscillates in simple harmonic motion, with amplitude A and period T. The particle starts from position x = A. What is
frozen [14]

Answer:

i guess it is D because,

y = A sin(wt)

w = \frac{2\pi }{T} and t = 3T/ 2

now, Y = A sin ( \frac{2\pi }{T} X \frac{3T}{2})

so, Y = 0radian

Explanation:

8 0
3 years ago
A square loop of wire is held in a uniform 0.24 T magnetic field directed perpendicular to the plane of the loop. The length of
NNADVOKAT [17]

Answer:

Explanation:

Given that,

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Then, dL/dt = -0.054m/s

When L is 14cm, what is the EMF induced?

L = 14cm = 0.14m

EMF is give as

ε = - dΦ/dt

Where flux is given as

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Substituting this into the EMF

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ε = - d(BL²)/dt

B is constant

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8 0
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