Answer:
it is the judicious use of energy to prevent wastage
<span>Reducing the distance between them. In theory, also increasing the mass; but you can't really change the mass of an object. However, you can compare the forces if you replace an object by a different object, which has a different mass.
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i hope this will work..
Answer:
The potential difference between the plates increases
Explanation:
As we know that the capacitance of the capacitor is given by:
(1)
where
q = charge
C = capacitance
V = Voltage or Potential Difference
Also, the capacitance of a parallel plate capacitor is given as:
(2)
where

A = Area of the plates
D = Separation distance between the plates
Now, from eqn (1) and (2):

Now, from the above eqn we can say that:
Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.
Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.
Answer:
Explanation:
Given that,
Magnetic field of 0.24T
B = 0.24T
Field perpendicular to plane i.e 90°
Rate of decrease of length of side of square is 5.4cm/s
dL/dt = 5.4cm/s = 0.054m/s
Since it is decreasing
Then, dL/dt = -0.054m/s
When L is 14cm, what is the EMF induced?
L = 14cm = 0.14m
EMF is give as
ε = - dΦ/dt
Where flux is given as
Φ = BA
Where A is the area of the square
A = L²
Then, Φ = BL²
Substituting this into the EMF
ε = - dΦ/dt
ε = - d(BL²)/dt
B is constant
ε = - Bd(L²)/dt
ε = -2BL dL/dr
ε = -2 × 0.24 × 0.14 × -0.054
ε = 3.63 × 10^-3 V
ε = 3.63mV