Ask question

Ask question

All categories

Tcecarenko [31]

3 years ago

15

A sound wave (a periodic longitudinal wave) from a loudspeaker travels from air into water. The frequency of the wave does not c

hange, because the loudspeaker producing the sound determines the frequency. The speed of sound in air is 343 m/s, whereas the speed in fresh water is 1482 m/s. When the sound wave enters the water, does its wavelength increase, decrease, or remain the same

1 answer:

Tanzania [10]3 years ago

6 0

Answer:

When the sound wave enters the water its wavelength increase.

Explanation:

Given:

Speed of sound in air $v = 343 \frac{m}{s}$

Speed of sound in fresh water $v' = 1482 \frac{m}{s}$

We know that when wave travel into one medium to another medium frequency doesn't change.

Velocity is given by,

$v = f \lambda$

In above equation frequency is constant,

So when sound wave enters the water wavelength increase because speed sound is increase in water as compare to air.

Therefore, when the sound wave enters the water its wavelength increase.

You might be interested in

For which length of wire are the readings of resistance the most precise

levacccp [35]

The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.

7 0

2 years ago

A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic

vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 $m^{2}$ </h3>

Explanation:

Given :

No. of turns in the first coil $N_{1} = 41$

No. of turns in the second coil $N_{2} = 123$

Area of first coil $A_{1} = 0.074 m^{2}$

According to the law of electromagnetic induction,

Induced emf = $-N \frac{d \phi}{dt}$

Where $\phi =$ magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

$-\frac{N_{1} d\phi _{1} }{dt_{1} } = -\frac{N_{2} d\phi _{2} }{dt_{2} }$

$\frac{N_{1} A_{1} dB_{1} }{dt_{1} } = \frac{N_{2} A_{2} dB_{2} }{dt_{2} }$

$A_{2} = \frac{N_{1} A_{1} }{N _{2} }$

$A_{2} = \frac{41 \times 0.074 }{123 }$

$A_{2} = 0.0246 = 0.025 m^{2}$

Therefore, the area of second coil is ≅ 0.025 $m^{2}$

4 0

3 years ago

What would be the best design for an experiment that tests how much water expands when frozen?

galben [10]

B. Purchase a small plastic container and mark 1-ounce increments on the outside to determine volume. Pour 5 ounces of water into the container, and place in the freezer for 8 hours. Compare the frozen or ending volume with the liquid or beginning volume.

<h3>How much water expands when frozen?</h3>

Ice is less denser than the liquid form. Water is the only known non-metallic substance that expands when it freezes because it is the unique property of water. Water density decreases and it expands approximately about 9% by volume. For calculating the expansion of water, plastic container is the best option. We know that water expands when the water freezes because it is a unique property of water which allows the survival of aquatic organisms.

So we can conclude that option B is the right answer.

Learn more about water here: brainly.com/question/1313076

#SPJ1

5 0

1 year ago

An object starts at 4m/s and accelerates to 6m/s in 10 seconds. Find its displacement.

Natalka [10]

Answer:

Explanation:

The 2 equations we need here are, first:

$a=\frac{v_f-v_0}{t}$ and then once we solve for the acceleration here:

$v^2=v_0^2+2a$ Δx

Solving for acceleration:

$a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2}$ and now we will use that in the other equation:

$6^2=4^2+2(\frac{1}{5})$ Δx and

36 = 16 + $\frac{2}{5}$ Δx and

20 = $\frac{2}{5}$ Δx and

$\frac{5}{2}(20)=$ Δx so

Δx = 50 m

6 0

2 years ago

Interstellar matter is composed of ____________ found between stars in a galaxy.

Illusion [34]

This should be dust and gas

4 0

2 years ago