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Tcecarenko [31]
3 years ago
15

A sound wave (a periodic longitudinal wave) from a loudspeaker travels from air into water. The frequency of the wave does not c

hange, because the loudspeaker producing the sound determines the frequency. The speed of sound in air is 343 m/s, whereas the speed in fresh water is 1482 m/s. When the sound wave enters the water, does its wavelength increase, decrease, or remain the same
Physics
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

When the sound wave enters the water its wavelength increase.

Explanation:

Given:

Speed of sound in air v = 343 \frac{m}{s}

Speed of sound in fresh water v' = 1482 \frac{m}{s}

We know that when wave travel into one medium to another medium frequency doesn't change.

Velocity is given by,

  v = f \lambda

In above equation frequency is constant,

So when sound wave enters the water wavelength increase because speed sound is increase in water as compare to air.

Therefore, when the sound wave enters the water its wavelength increase.

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Answer:

a

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Two radio antennas A and B radiate in phase. Antenna B is a distance of 120 m to the right of antenna A. Consider point Q along
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Answer:

240 m

120 m

Explanation:

d = Path difference = 120 m

For destructive interference

Path difference

d=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2d\\\Rightarrow \lambda=2\times 120\\\Rightarrow \lambda=240\ m

The longest wavelength is 240 m

For constructive interference

d=\lambda\\\Rightarrow 120\ m=\lambda

The longest wavelength is 120 m

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How much heat is required to convert 12.0 g of ice at -10.0°C to steam at 100.0°C. Express your answer in joules, calories, and
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Scientist Jordan makes a discovery and publishes the results for other scientists to read. Scientist Leesha tries to repeat the
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Answer:

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5 0
2 years ago
The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm
Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential  is given by;

\rm V=Ed

\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V=  10 \frac{Nm}{C} = 10 \frac{J}{C}  = 10 V.

The work is defined as the product of the potential difference and charge of an electron.

\rm W= 10 \times  1.602 x 10^{-19} \\\\\ \rm W=  1.6 x 10^{-18 }J

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

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