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AURORKA [14]
1 year ago
13

in a certain nuclear reactor, neutrons suddenly collide with carbon nuclei, which have 12 times the mass of neutrons. in a head-

on elastic collision with a stationary carbon nucleus, what fraction of its initial speed does the neutron have after the collision?
Physics
1 answer:
castortr0y [4]1 year ago
5 0

carbon atomic mass Equals m2

neutron mass = M,

as mg 12m1 = the speed of the neutron following a collision

m1 - m2 / m1 + m2 * u1 = v1

= [(-12m1+m1) / 13m1] * u1

= [(-12+1) 13] * u1

v1 = -11/13*u1

Neutron speed equals 11/13 starting speed.

Response: 11/13

A nuclear reactor is a device used to start and regulate nuclear chain reactions involving fission or nuclear fusion. Nuclear reactors are used in nuclear power plants to produce electricity and in nuclear propulsion for ships.

The neutron, symbol n or n0, is a subatomic particle with a neutral charge and slightly more mass than a proton. Atomic nuclei consist of protons and neutrons.

The element with atomic number 6 carbon has small, straightforward atoms. Six positively charged protons make up the nucleus, and there are six electrons outside the nucleus that are split between two shells.

To know more about nuclear reactor, click on the link below:

brainly.com/question/23160065

#SPJ4

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What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source
Alex_Xolod [135]

Answer:

The magnetic field strength  required to hold anti-protons, moving at 5.70 ✕ 10⁷ m/s in a circular path of 3.20 m in radius is 0.186 T.

Explanation:

To solve the question we note that the magnetic force on a moving charge is given by

F = q·v·B

Where

q = Charge

v = Velocity of the charge =5.70 ✕ 10⁷ m/s

B = Magnetic field

Based on Newton's second law,

Force = Mass, m × Acceleration, a = m × a

Where:

a = Acceleration

m = Mass of anti-proton = Mass of proton = 1.6726219 × 10⁻²⁷ kg

We note that for circular motion, acceleration a is given by

\alpha = \frac{v^{2} }{r} .

Where:

r = Radius = 3.20 m

Therefore, for the circular motion, force, F = \frac{m\cdot v^{2} }{r}

Equating the magnetic force equation to the circular force equation, we have

\frac{m\cdot v^{2} }{r} = q·v·B So that, we find B by making the subject of the formula as follows

B= \frac{m\times v^{2} }{r\times q \times v} . Which gives

B= \frac{m\times v }{r\times q} =  \frac{(1.6726219 \times 10^{-27}) \times (5.7\times 10^{7}) }{(3.20)\times (1.602\times 10^{-19}) } =  0.186 T

The magnetic field strength is

B = 0.186 T

4 0
3 years ago
A worker exerts a pulling force on a box. The worker exerts this force by attaching a rope to the box and pulling on the rope so
shusha [124]

Answer:

<em>The magnitude of the pulling force is 20.66% of the gravitational force acting on the box</em>

Explanation:

<u>Accelerated Motion</u>

The net force exerted on a body is the (vector) sum of all forces applied to the body. The net force can be decomposed in its rectangular components and the dynamics of the body can be studied in each direction x,y separately.

Let's start off by calculating the acceleration the worker gives to the box when pulling it. The distance traveled by the box initially at rest in a time t at an acceleration a is given by

\displaystyle x=\frac{at^2}{2}

Solving for a

\displaystyle a=\frac{2x}{t^2}

\displaystyle a=\frac{2\cdot 10}{5.12^2}

a=0.763\ m/s^2

Now we analyze the geometric of the forces applied to the box. Please refer to the free body diagram provided below.

The forces in the y-axis must be in equilibrium since no movement takes place there, thus, being g the acceleration of gravity:

T_y+N=m.g

There Ty is the vertical component of the tension of the rope, N is the normal force, and m is the mass of the box

The decomposition of T gives us

T_y=Tsin\theta

T_x=Tcos\theta

Solving the above equation for N

Tsin\theta+N=m.g

N=m.g-Tsin\theta\text{..........[1]}

Now for the x-axis, there are two forces acting on the box, the x-component of the tension and the friction force Fr. Those forces are not equilibrated, thus acceleration is produced:

Tcos\theta-F_r=m.a

Recalling that

F_r=\mu N

Tcos\theta-\mu N=m.a

Replacing N from [1]

Tcos\theta-\mu (m.g-Tsin\theta)=m.a

Operating

Tcos\theta-\mu m.g+\mu Tsin\theta=m.a

Solving for T

T(cos\theta+\mu sin\theta)=m.a+\mu m.g

\displaystyle T=\frac{m.a+\mu m.g}{cos\theta+\mu sin\theta}

\displaystyle T=m\frac{a+\mu g}{cos\theta+\mu sin\theta}

We don't know the value of m, thus we'll plug in the rest of the data

\displaystyle T=m\frac{0.763+0.10\cdot 9.8}{cos36.8^o+0.10 sin36.8^o}

T=2.0252m

Dividing by the weight of the box m.g

T/(m.g)=2.0252/9.8=0.2066

Thus, the magnitude of the pulling force is 20.66% of the gravitational force acting on the box

7 0
3 years ago
. An experimental rocket plane lands on skids on a dry lake bed. If it’s traveling at 80.0 m/s when it touches down, how far doe
kobusy [5.1K]

Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

element

mixture

compound

2.

Which of the following materials is a substance?

air

gasoline

stainless steel

silver

3.

The first figure in a properly written chemical symbol always is _____.

boldfaced

capitalized

italicized

underlined

4.

Which of the following represents a compound?

H

H-3

H2O

O-16

5. What do chemical symbols and formulas represent, respectively?

elements and compounds

atoms and mixtures

compounds and mixtures

elements and ions

Explanation:

5 0
2 years ago
If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?
bija089 [108]

<em>Mass of fuel has the airplane took on = 167.89 kg</em>

\boxed{\boxed{\bold{Further~explanation}}}

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm3 or kg / m3

  • Density formula:

\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

If we look at fuel capacity data such as Airbus which has a maximum capacity of 204, 5 liters then the mass of fuel it carries is

ρ = 0.821 gr / ml = 0.821 kg / l

  • mass = ρ . V

mass = 0.821 kg / l . 204.5 liters

mass = 167.89 kg

So the mass of fuel carried by aircraft is 167.89 kg

\boxed{\boxed{\bold{Learn~more}}}

density and molarity of the solution brainly.com/question/8151398

the percent of acetic acid in the vinegar brainly.com/question/3001349

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the relative density of the fuel

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Keywords: density, mass, volume, aircraft, fuel, derivative quantities

7 0
4 years ago
Read 2 more answers
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