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AURORKA [14]
1 year ago
13

in a certain nuclear reactor, neutrons suddenly collide with carbon nuclei, which have 12 times the mass of neutrons. in a head-

on elastic collision with a stationary carbon nucleus, what fraction of its initial speed does the neutron have after the collision?
Physics
1 answer:
castortr0y [4]1 year ago
5 0

carbon atomic mass Equals m2

neutron mass = M,

as mg 12m1 = the speed of the neutron following a collision

m1 - m2 / m1 + m2 * u1 = v1

= [(-12m1+m1) / 13m1] * u1

= [(-12+1) 13] * u1

v1 = -11/13*u1

Neutron speed equals 11/13 starting speed.

Response: 11/13

A nuclear reactor is a device used to start and regulate nuclear chain reactions involving fission or nuclear fusion. Nuclear reactors are used in nuclear power plants to produce electricity and in nuclear propulsion for ships.

The neutron, symbol n or n0, is a subatomic particle with a neutral charge and slightly more mass than a proton. Atomic nuclei consist of protons and neutrons.

The element with atomic number 6 carbon has small, straightforward atoms. Six positively charged protons make up the nucleus, and there are six electrons outside the nucleus that are split between two shells.

To know more about nuclear reactor, click on the link below:

brainly.com/question/23160065

#SPJ4

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alexgriva [62]

Answer: Yes

Explanation:

Velocity V is defined as the distance traveled d in a specific time t:

V=\frac{d}{t}

If you are traveling at V=100 km/h a distance d=16 m, then the time it will take you to be at work is:

t=\frac{d}{V}=\frac{16 km}{100 km/h}

t=0.16 h

This means you will make it on time, because this time is less than 0.25 h.

4 0
4 years ago
A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis
Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

4 0
3 years ago
What causes wind how does the process reverse itself between day and night?
iris [78.8K]
<span>Wind is nature's way of balancing the temperature between hot and cold. Wind always flows from heat to cool. When night falls, the air cools. And since it gets cooler at night it reverses.</span>
5 0
3 years ago
What type of motion occurs when an object spins around an axis without altering its linear position?
dimulka [17.4K]
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3 years ago
A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?
Rama09 [41]

Answer:

The y-component of the normal force is 45.74 N.

Explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill, \theta=21^{\circ}

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5\times 9.8\ \cos(21)\\\\F_y=45.74\ N

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.

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3 years ago
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