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Ivenika [448]
3 years ago
15

A battery has an electric potential of 1.5V and transfers 10.0 C between the two terminals. How much work was done?

Physics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

15 Joules

Explanation:

work = charge x potential difference

= 10 x 1.5

= 15

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A motor has an armature resistance of 3.75 Ω . Part A If it draws 9.10 A when running at full speed and connected to a 120-V lin
bulgar [2K]

Back emf is 85.9 V.

<u>Explanation:</u>

Given-

Resistance, R = 3.75Ω

Current, I = 9.1 A

Supply Voltage, V = 120 V

Back emf = ?

Assumption - There is no effects of inductance.

A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.

So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,

The voltage across the resistance would be

v = I x R

  = 9.1 x 3.75

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