Answer:
The simple definition of water hardness is the amount of dissolved calcium and magnesium in the water. Hard water is high in dissolved minerals, largely calcium and magnesium.
Explanation:
Answer:
First you multiply the number of atoms by the atomic mass of the element.This gives you the molar mass. Then you divide the molar mass by the number of grams in order to find the number of moles.
Hope this helps!
Neutron, neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen. It has no electric charge and a rest mass equal to 1.67493 × 10−27 kg—marginally greater than that of the proton but nearly 1,839 times greater than that of the electron.
At conditions 50 K and 20 kPa of temperature and pressure
would helium behave most like an ideal gas. The answer is number 1. This is because
the temperature is so low and the pressure is low too.
Answer:
1. 0.97 V
2. ![Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)](https://tex.z-dn.net/?f=Al_%28_s_%29%2FAl%5E%2B%5E3~_%28_a_q_%29~%2F%2F~Ag%5E%2B~_%28_a_q_%29%2FAg_%28_s_%29)
Explanation:
In this case, we can start with the <u>half-reactions</u>:
![Ag^+~_(_a_q_)->~Ag_(_s_)](https://tex.z-dn.net/?f=Ag%5E%2B~_%28_a_q_%29-%3E~Ag_%28_s_%29)
![Al_(_s_)~->~Al^+^3~_(_a_q_)](https://tex.z-dn.net/?f=Al_%28_s_%29~-%3E~Al%5E%2B%5E3~_%28_a_q_%29)
With this in mind we can <u>add the electrons</u>:
<u>Reduction</u>
<u>Oxidation</u>
The reduction potential values for each half-reaction are:
- 0.69 V
-1.66 V
In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:
+1.66 V
Finally, to calculate the overall potential we have to <u>add</u> the two values:
1.66 V - 0.69 V = <u>0.97 V</u>
For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:
![Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)](https://tex.z-dn.net/?f=Al_%28_s_%29%2FAl%5E%2B%5E3~_%28_a_q_%29~%2F%2F~Ag%5E%2B~_%28_a_q_%29%2F~Ag_%28_s_%29)
I hope it helps!