3. In which process do substances have to be in direct contact when heat moves

Given 6193 mL of a gas at 62.3 °C. What is its volume at 38.1 °C?

Luden [163]

Answer:

5746.0 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 6193.0 mL, T₁ = 62.3°C + 273 = 335.3 K.

V₂ = ??? mL, T₂ = 38.1°C + 273 = 311.1 K.

∴ V₂ = V₁T₂/T₁ = (6193.0 mL)(311.1 K)/(335.3 K) = 5746.0 mL.

5 0

3 years ago

How many molecules are in 85g of silver nitrate?

maksim [4K]

<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Writing Compounds
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

85 g AgNO₃ (silver nitrate)

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

Step 3: Convert

Set up: $\displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})$
Multiply/Divide: $\displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0

3 years ago

BRAINLIESTTT ASAP!!!! PLEASE HELP ME :)

Elan Coil [88]

Answer:

1s² 2s²2p³

Explanation:

If the atom has seven electrons, it is Element 7 (nitrogen).

In the Periodic Table, you count the electrons in all the subshells up to

No. 7.

In the first Period, you have filled the 1s level (2 electrons).

In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.

Thus, the electron configuration is

1s² 2s²2p³

Note how the superscripts tell you the number of electrons in each subshell: 2 + 2 + 3 = 7.

6 0

3 years ago

A prion is an infectious self-reproducing protein structure. true or false

Alexandra [31]

Answer:

True is the correct answer.

Explanation:

The statement that a prion is an infectious, self-reproducing protein structure is true.

prion is an infectious particle and they do not have genetic material.

Prion present in the brain region that results in deadly neurodegenerative illnesses in humans and animals.

Prions are the self-producing proteinaceous infectious capable of transferring infection in the absence of the nucleic acids.
prions enter in the brain by an infection and they emerge from the variation in the gene that encodes the protein and once the prions present in the brain multiply by causing the benign proteins to refold into an abnormal form.

8 0

3 years ago

What range on the glycemic index (GI) corresponds to a high glycemic impact food? 70 and above 56 to 69 1 to 55 1 to 35

german

Answer: 70 and above

Explanation:

This is a fact.

8 0

2 years ago