Answer:
The limiting reactant is B.
Explanation:
The equation for the reaction is given below:
2A + 3B —> C + D
The limiting reactant can be obtained as follow:
From the equation above,
2 units of A reacted with 3 units of B.
Therefore, 5 units of A will react with = (5 x 3) /2 = 7.5 units of B.
From the calculation made above, we can see that it will take a higher unit of B i.e 7.5 units than what was given i.e 6 units to react completely with 5 units of A.
Therefore, B is the limiting reactant and A is the excess reactant.
A metallic bond is a force that holds atoms together in a metallic substance.
What are the answer choices???
In the compound potassium nitrate (KNO3), the atoms within the nitrate ion are held together with COVALENT bonding, and the potassium ion and nitrate ion are held together by IONIC bonding.
A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs. Covalent bond is formed between two non-metals.
Ionic bonds form when one atom gives up one or more electrons to another atom. It is the complete transfer of valence electron(s) between oppositely charged atoms. Ionic bond is formed between metal (electropositive element) and non-metal(electronegative element)
In nitrate ions the Nitrogen (N) and Oxygen (O) both are non-metals and it involves the sharing of electron pairs between N and O atoms, so the bonding in Nitrate (
) ion is covalent bonding.
In potassium nitrate , Potassium (K) is a metal and Nitrate (
) ion is non-metal and it involves the complete transfer of valence electron between oppositely charged atoms (K+) and (
). So the bonding between Potassium and Nitrate is Ionic bonding.
NOTE : Bonding between Non-metals is Covalent bonding.
Bonding between Metal and Non-metals is Ionic bonding.
Answer:
C = 0.7385J/g°C
Explanation:
Heat energy (Q) = 54J
Mass (m) = 2.47g
Initial temperature (T1) = 17.10°C
Final temperature (T2) = 46.70°C
Specific heat capacity of substance (c) = ?
Heat energy of a substance (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of substance = T2 - T1
Q = mc∇T
Q = mc (T2 - T1)
54 = 2.47 * c * (46.70 - 17.10)
54 = 2.47 * 29.6 * c
54 = 73.112c
C = 54 / 73.112
C = 0.7385
Specific heat capacity of the substance is 0.7385J/g°C
B.
The specific heat capacity of the above substance does not match any metal in the periodic table, however the closest to it was potassium with a value of 0.7536J/g°C and silicone with value of 0.711756J/g°C