If the Poisson’s ratio of a 5 mm X 5 mm titanium alloy pin is 0.31 and it is elastically loaded
1 answer:
The new dimensions of the titanium alloy pin will be that the width is 0.0775 mm and the length is 4.9225m.
<h3>What is Poisson's ratio?</h3>The Poisson's ratio is the proportion of a material's change in width per unit width to its change in length per unit length due to strain. In order for a stable, isotropic, linear elastic material to have a positive Young's modulus, shear modulus, and bulk modulus, the Poisson's ratio must be between 1.0 and +0.5. Poisson's ratio values for the majority of materials fall between 0.0 and 0.5.
The formula for the longitudinal strain is:
= Change in length / Initial length
Based on the information, the longitudinal strain will be:
= 105 - 100 / 100
= 0.05
Poisson ratio will be illustrated as the change in the width divided by the longitudinal strain. :
0.31 = ∆w/5 / 0.05
∆w = 0.0775 mm
New side length will be the difference in the changes in the dimensions:
= w - ∆w
= 5 - 0.0775
= 4.9225m
Learn more about Poisson on:
#SPJ1
You might be interested in
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
