If the Poisson’s ratio of a 5 mm X 5 mm titanium alloy pin is 0.31 and it is elastically loaded
1 answer:
The new dimensions of the titanium alloy pin will be that the width is 0.0775 mm and the length is 4.9225m.
<h3>What is Poisson's ratio?</h3>The Poisson's ratio is the proportion of a material's change in width per unit width to its change in length per unit length due to strain. In order for a stable, isotropic, linear elastic material to have a positive Young's modulus, shear modulus, and bulk modulus, the Poisson's ratio must be between 1.0 and +0.5. Poisson's ratio values for the majority of materials fall between 0.0 and 0.5.
The formula for the longitudinal strain is:
= Change in length / Initial length
Based on the information, the longitudinal strain will be:
= 105 - 100 / 100
= 0.05
Poisson ratio will be illustrated as the change in the width divided by the longitudinal strain. :
0.31 = ∆w/5 / 0.05
∆w = 0.0775 mm
New side length will be the difference in the changes in the dimensions:
= w - ∆w
= 5 - 0.0775
= 4.9225m
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Answer: The energy system related to your question is missing attached below is the energy system.
answer:
a) Work done = Net heat transfer
Q1 - Q2 + Q + W = 0
b) rate of work input ( W ) = 6.88 kW
Explanation:
Assuming CPair = 1.005 KJ/Kg/K
<u>Write the First law balance around the system and rate of work input to the system</u>
First law balance ( thermodynamics ) :
Work done = Net heat transfer
Q1 - Q2 + Q + W = 0 ---- ( 1 )
rate of work input into the system
W = Q2 - Q1 - Q -------- ( 2 )
where : Q2 = mCp T = 1.65 * 1.005 * 293 = 485.86 Kw
Q2 = mCp T = 1.65 * 1.005 * 308 = 510.74 Kw
Q = 18 Kw
Insert values into equation 2 above
W = 6.88 Kw
Answer:
<h2>hope it helps you see the attachment for further information .....✌✌✌✌✌</h2>