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Tasya [4]
1 year ago
7

A liquid jet vj of diameter dj strikes a fixed cone and deflects back as a conical sheet at the same velocity. find the cone ang

le θ for which the restraining force f = (3/2)rhoajvj^2 .
Engineering
1 answer:
dmitriy555 [2]1 year ago
7 0

Answer:

lol i cant real it sorry

Explanation:

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A stomp rocket is a toy consisting of a hose connected to a blast pad (i.e., an air bladder) at one end and to a short pipe moun
lesya [120]

Answer:

Explanation:

The detailed steps is as shown in the attachment.

8 0
2 years ago
What should you release to re-establish vehicle control and tire traction?
MrMuchimi

Answer: The accelerator and the brakes.

6 0
2 years ago
An asphalt concrete mixture includes 94% aggregate by weight. The specific gravities of aggregate and asphalt are 2.65 and 1.0,
garik1379 [7]

Answer:

2.0%

Explanation:

Percentage of aggregate = 94%

Specific gravity = 2.65

Specific gravity of asphalt = 1.9

Density of mix = 147pcf = 147lb/ft³

Total weight of mix: (volume = 1ft³)

= (147lb/ft³)(1ft³)

= 147lb

Percentage weight of asphalt in<u> mix:</u>

100% - 94%

= 6%

Weight of asphalt binders

= 6% x 147lb

= 8.82lb

Weight of aggregate in mix:

= 94% x 147

= 138.18lb

Specific weight of asphalt binder:

(Gab)(Yw)

Yw = specific Weight of water

= 62.4lb

Gab = specific gravity of asphalt binder

= 1.0

(62.4lb)(1.0)

= 62.4 lb/ft³

Volume of asphalt in binder:

8.82/62.4

= 0.14ft³

Specific weight of binder in mix:

2.65 x 62.4lb/ft³

= 165.36 lb/ft³

Volume of aggregate:

= 138.18/165.36

= 0.84ft³

Volume of void in the mix:

1ft³ - 0.84ft³ - 0.14ft³

= 0.02ft³

<u>The percentage of void in total mix:</u>

VTM = (0.02ft³/1ft³)100

= 2.0%

8 0
2 years ago
How can I solve this sequence problem?​
Vinvika [58]

Answer:

Podes  hablar en español?

Explanation:

8 0
2 years ago
Read 2 more answers
Write a program with total change amount as an integer input, and
AURORKA [14]

Answer:

amount = int(input())

#Check if input is less than 1

if amount<=0:

    print("No change")

else: #If otherwise

    #Convert amount to various coins

    dollar = int(amount/100) #Convert to dollar

    amount = amount % 100 #Get remainder after conversion

    quarter = int(amount/25) #Convert to quarters

    amount = amount % 25 #Get remainder after conversion

    dime = int(amount/10) #Convert to dimes

    amount = amount % 10 #Get remainder after conversion

    nickel = int(amount/5) #Convert to nickel

    penny = amount % 5 #Get remainder after conversion

    #Print results

    if dollar >= 1:

          if dollar == 1:

                print(str(dollar)+" Dollar")

          else:

                print(str(dollar)+" Dollars")

    if quarter >= 1:

          if quarter == 1:

                print(str(quarter)+" Quarter")

          else:

                print(str(quarter)+" Quarters")

    if dime >= 1:

          if dime == 1:

                print(str(dime)+" Dime")

          else:

                print(str(dime)+" Dimes")

    if nickel >= 1:

          if nickel == 1:

                print(str(nickel)+" Nickel")

          else:

                print(str(nickel)+" Nickels")

    if penny >= 1:

          if penny == 1:

                print(str(penny)+" Penny")

          else:

                print(str(penny)+" Pennies")

Explanation:

8 0
3 years ago
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