Answer:
1373.4 N/m
Explanation:
Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then
Also, F=gm hence the above formula is modified as
Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then
Answer:
Find the dimension of each and every quantity in all the options to check whether they are the same or not. We can use any one formula of each identity to find its dimension.
Complete step by step solution:
To find the dimension of a quantity, we can use any formula related to that quantity but we will use the easiest ones to save time.
Force-
from Newton’s law of motion,
F=maF=ma
Dimension of force =[M][LT−2]=[MLT−2]=[M][LT−2]=[MLT−2]
Work done-
W=F×sW=F×s
Dimension of work=[MLT−2][L]=[ML2T−2]=[MLT−2][L]=[ML2T−2]
Momentum-
p=mvp=mv
Dimension of momentum=[M][LT1]=[MLT−1]=[M][LT1]=[MLT−1]
Impulse-
I=F×tI=F×t
Dimension of impulse=[MLT−2][T]=[
Atomic disguise makes helium look like hydrogen. ... A helium atom consists of a nucleus containing two positively charged protons and two neutrons, encircled by two orbiting electrons which carry a negative charge. A hydrogen atom has just one proton and one electron
Answer:
6.86 × 10²⁴ kg
Explanation:
The mass of the earth m = density of earth, ρ × volume of earth, V
m = ρV
The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m
Since m = ρV
m = ρ4πr³/3
So, substituting the values of the variables into the equation for the mass of the earth, m, we have
m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3
m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3
m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3
m = 6546105.64378π × 10¹⁸ kg/3
m = 20565197.400122 × 10¹⁸ kg/3
m = 6855065.8 × 10¹⁸ kg
m = 6.8550658 × 10²⁴ kg
m ≅ 6.86 × 10²⁴ kg
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