First of all, let's write the equation of motions on both horizontal (x) and vertical (y) axis. It's a uniform motion on the x-axis, with constant speed

, and an accelerated motion on the y-axis, with initial speed

and acceleration

:


where the negative sign in front of g means the acceleration points towards negative direction of y-axis (downward).
To find the distance from the landing point, we should find first the time at which the projectile hits the ground. This can be found by requiring

Therefore:

which has two solutions:

is the time of the beginning of the motion,

is the time at which the projectile hits the ground.
Now, we can find the distance covered on the horizontal axis during this time, and this is the distance from launching to landing point:
C, N and O all belong to the same period, in which it's 2nd Period.
Answer:
1. it is laminar flow
2. it is not fully developed
3.Re=63.156
4. entrance length is the entrance diameter which is 4.1-mm-
Explanation:
A soft drink with the properties of 10 oC water is sucked through a 4.1-mm-diameter, 0.25-m-long straw at a rate of 4.1 cm3/s.
(a) Is the flow at the outlet of the straw laminar?
(b) Is it fully developed? To explain calculate
(c) the Reynolds number and
(d) the entrance length
note te following
For&pipe&flow:&
Re&<&2100 laminar&flow&
Re&>&4000 turbulent&flow&
kinematic viscosity of water at 10 oCis 1.267E-6m^2/S
Re=vl/k.viscosity
v=q/A
q=4.1 cm3/s=4.1*10^-6m3/s
A=3.142*0.0041/4
A=0.00322m2
v=0.000318m/s
l= 0.25-m
RE=0.000318m/s*0.25/( 1.267E-6m^2/S)
Re=63.156
since re<2100 , it is laminar flow
2. it is not fully developed
3.Re=63.156
4. entrance length is the entrance diameter wic is 4.1-mm-
The answer to the question is (C)
Hope this helps :)