A 5 cm object is 6 cm from a convex lens, which has a focal length of 7 cm. What is the distance of the image from the lens
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Answer:
The total electric potential at mid way due to 'q' is
The net Electric field at midway due to 'q' is 0.
Solution:
According to the question, the separation between two parallel plates, plate A and plate B (say) = d
The electric potential at a distance d due to 'Q' is:
Now, for the Electric potential for the two plates A and B at midway between the plates due to 'q':
For plate A,
Similar is the case with plate B:
Since the electric potential is a scalar quantity, the net or total potential is given as the sum of the potential for the two plates:
Now,
The Electric field due to charge Q at a distance is given by:
Now, if the charge q is mid way between the field, then distance is .
Electric Field at plate A, at midway due to charge q:
Similarly, for plate B:
Both the fields for plate A and B are due to charge 'q' and as such will be equal in magnitude with direction of fields opposite to each other and hence cancels out making net Electric field zero.