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Kaylis [27]
3 years ago
7

Use the data provided to calculate the amount of heat generated for each cylinder height. Round your answers to the nearest tent

h.
100m: kJ
200 m: kJ
1000 m: kJ

Physics
2 answers:
luda_lava [24]3 years ago
8 0

100m: 4.9 kJ

200m: 9.8 kJ

1000m: 49.1 kJ


VladimirAG [237]3 years ago
7 0

Answer:

100m: 4.9 kJ

200m: 9.8 kJ

1000m: 49.1 kJ

Explanation:

In order to calculate this, you just have to calculate the PE of every cilynder, and as you know the PE is calculated with the next formula:

PE=G*H*M\\PE=Potential-Energy\\G=Gravity\\H=Height\\M=Mass

SO we just hve to insert the values into the formula to get our results, remember that the height will change with every sample because we are putting the cylinder at different heights:

100m:

PE=G*H*M\\PE=9.8*100*5kg= 4900 joules=4.9Kj

200m:

PE=G*H*M\\PE=9.8*200*1kg= 9800 joules=9.8Kj

1000m:

PE=G*H*M\\PE=9.8*1000*1kg= 49100 joules=49.1Kj

And you have the different heat generated by each cilynder at different heights.

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A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 10.0 m/s2. A 20 kg ma
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Answer

given,

mass = 100 kg

acceleration = 10 m/s²

A mass 20 kg slides over 100 kg block

acceleration = 3 m/s²

horizontal friction exerted by the 100 kg block on 20 kg

using newton's second law

F - f = 0

F = f

f = ma

f = 20 × 3

f = 60 N

now net force acting on the 100 kg block

F_net = m a

F_net = 100 x 10

F_net = 1000 N

after 20 kg block falls the acceleration of the bock

F = 1000 +60

F = 1060 N

acceleartion on the block

a = \dfrac{F}{m}

a = \dfrac{1060}{100}

a = 10.60 m/s²

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3 years ago
If a lawn mower is pushed with a distance of 30 meters and 12N-m of work is exerted, calculate the force.
Nimfa-mama [501]

Answer:

Explanation:

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3 years ago
HELP 30 POINTS
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A characteristic in an experiment, such as how much food, how much space, how hot or how cold, is termed a ____________. (spelli
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14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards
quester [9]

The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

500N = 90kg x a

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Now, the weight if the lineman is 120kg, the force applied by him is 500N.

So, from the formula, his acceleration A will be,

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both of them will have acceleration in the same direction,

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