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Kaylis [27]
3 years ago
7

Use the data provided to calculate the amount of heat generated for each cylinder height. Round your answers to the nearest tent

h.
100m: kJ
200 m: kJ
1000 m: kJ

Physics
2 answers:
luda_lava [24]3 years ago
8 0

100m: 4.9 kJ

200m: 9.8 kJ

1000m: 49.1 kJ


VladimirAG [237]3 years ago
7 0

Answer:

100m: 4.9 kJ

200m: 9.8 kJ

1000m: 49.1 kJ

Explanation:

In order to calculate this, you just have to calculate the PE of every cilynder, and as you know the PE is calculated with the next formula:

PE=G*H*M\\PE=Potential-Energy\\G=Gravity\\H=Height\\M=Mass

SO we just hve to insert the values into the formula to get our results, remember that the height will change with every sample because we are putting the cylinder at different heights:

100m:

PE=G*H*M\\PE=9.8*100*5kg= 4900 joules=4.9Kj

200m:

PE=G*H*M\\PE=9.8*200*1kg= 9800 joules=9.8Kj

1000m:

PE=G*H*M\\PE=9.8*1000*1kg= 49100 joules=49.1Kj

And you have the different heat generated by each cilynder at different heights.

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Answer:

so angular velocity is 7.13128 sec−1

Explanation:

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angular velocity

solution

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now put all these value in equation 1 and we get angular velocity i.e.

angular velocity =  velocity ( v)  / (displacement²  +  distance²)

angular velocity = 2.2  / (0.22²  +  0.51²)

angular velocity = 2.2 / 0.3085

angular velocity = 7.13128

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A man is sitting in the outfield bleachers watching a baseball game through binoculars. Which is MOST LIKELY true?
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A go-kart and rider have a mass of 14 kg. If the cart accelerates at 6 m/s² during a 40 m sprint in 100 seconds, how much power
Nutka1998 [239]

Answer:

<em>P=33.6 \ W</em>

Explanation:

<u>Mechanical Work and Power</u>

Work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being \vec F the force vector and \vec s the displacement vector, the work is calculated as:

W=\vec F\cdot \vec s

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Mechanical Power is the amount of energy transferred or converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\displaystyle P=\frac {W}{t}

Where W is the work and t is the time.

If an object of mass m has an acceleration a, the net force is:

F=m.a

The go-kart and rider have a mass of m=14 kg and accelerate at 6 m/s^2, thus the net force applied is:

F=14\cdot 6 = 84\ N

The work done by the cart when traveling d= 40 m is:

W=84\cdot 40

W=3,360\ J

Finally, the power for t= 100 seconds is:

\displaystyle P=\frac {3,360}{100}

P=33.6 \ W

5 0
3 years ago
Consider a concave mirror that has a focal length f. In terms of f, determine the object distances that will produce a magnifica
Aleks04 [339]

We have that the magnification of each focal length is given respectively as

A) has u=3\frac{f}{2}

B) has u=4\frac{f}{3}

C) has  u=5\frac{f}{4}

From the question we are told that:

Focal Length F

Generally, the equation for Magnification is mathematically given by

M=\frac{-v}{u}

Therefore

v=2u

For A

M=-2

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{2u}

Therefore

u=3\frac{f}{2}

For B

M=-3

Therefore

v=3u

Where

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{3u}

Therefore

u=4\frac{f}{3}

For C

M=-4

Therefore

v=4u

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{4u}

Therefore

u=5\frac{f}{4}

Conclusion

From the calculations above we can rightly say that the magnifications of the values above are

A has u=3\frac{f}{2}

B has u=4\frac{f}{3}

C has  u=5\frac{f}{4}

For more information on this visit

brainly.com/question/14468351

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