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yuradex [85]
3 years ago
11

Which change will cause the gravitational force between a baseball and a soccer ball to increase? Select three options.

Physics
1 answer:
Sholpan [36]3 years ago
5 0

moving the balls closer together

pumping more air into the soccer ball

putting the baseball in a plastic case

Explanation:

The gravitational force between the baseball and the soccer ball will increase if the moving balls are closer together, pumping more air into the soccer ball and putting the baseball in a plastic case.

According to Newton's law of universal gravitation "the force between two masses is proportional to the magnitude of their mass and inversely proportional the square of the distances between them". It is mathematically expressed as:

   Fgravity = G\frac{M_{1} M_{2}  }{r^{2} }

Where G is a constant called the universal gravitation constant.

           M1 is the mass of particle 1

            M2 is the mass of particle 2

             r is the distance between them.

The force of gravity increases as their masses increase and also as the distance between the bodies reduce.

From the options:

Moving the balls closer together                       distance reducing

Pumping more air into the soccer ball               mass increasing

Putting the baseball in a plastic case                mass increasing

Learn more:

Universal Gravitation brainly.com/question/1724648

#learnwithBrainly

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Answer:

B

Explanation:

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What are some climate facts
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3 years ago
A ball is dropped and falls with an acceleration of 9.8 m/s2 downward. It hits the ground with a velocity of 49 m/s downward. Ho
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Hey!

NOTE-:

u= initial velocity
v= final velocity
g= acceleration due to gravity
t= time

u= 0
v= 49 m/s
t=?
g= 9.8 m/s^2

Using first equation of motion -

v-u=at
49-0= 9.8×t
49 = 9.8t
49/9.8= t
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6 0
3 years ago
An electron is released from rest on the axis of a uniform positively charged ring, 0.200 m from the ring's center. If the linea
melisa1 [442]

Answer:

Velocity of the electron at the centre of the ring, v=1.37\times10^7\ \rm m/s

Explanation:

<u>Given:</u>

  • Linear charge density of the ring=0.1\ \rm \mu C/m
  • Radius of the ring R=0.2 m
  • Distance of point from the centre of the ring=x=0.2 m

Total charge of the ring

Q=0.1\times2\pi R\\Q=0.1\times2\pi 0.4\\Q=0.251\ \rm \mu C

Potential due the ring at a distance x from the centre of the rings is given by

V=\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\

The potential difference when the electron moves from x=0.2 m to the centre of the ring is given by

\Delta V=\dfrac{kQ}{R}-\dfrac{kQ}{\sqrt{(R^2+x^2)}}\\\Delta V={9\times10^9\times0.251\times10^{-6}} \left( \dfrac{1}{0.4}-\dfrac{1}{\sqrt{(0.4^2+0.2^2)}} \right )\\\Delta V=5.12\times10^2\ \rm V

Let\Delta U be the change in potential Energy given by

\Delta U=e\times \Delta V\\\Delta U=1.67\times10^{-19}\times5.12\times10^{2}\\\Delta U=8.55\times10^{-17}\ \rm J

Change in Potential Energy of the electron will be equal to the change in kinetic Energy of the electron

\Delta U=\dfrac{mv^2}{2}\\8.55\times10^{-17}=\dfrac{9.1\times10^{-31}v^2}{2}\\v=1.37\times10^7\ \rm m/s

So the electron will be moving with v=1.37\times10^7\ \rm m/s

5 0
3 years ago
A solenoid has a radius Rs = 14.0 cm, length L = 3.50 m, and Ns = 6500 turns. The current in the solenoid decreases at the rate
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Answer:

E = 58.7 V/m

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As we know that flux linked with the coil is given as

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here we have

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now for induced electric field in the coil is linked with the EMF as

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3 0
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