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3 years ago

Which term describes the object that a satellite revolves around?

Physics

2 answers:

m_a_m_a [10]3 years ago

6 0

The object that a satellite revolves around is the <em>central body</em> of the system. <em>(C)</em>

For example:

-- The central body of the solar system is the Sun.

-- The central body for TV satellites, GPS satellites, weather satellites, and the International Space Station is the Earth.

-- The central body for Phobos and Deimos is Mars.

This should be a pretty easy question to answer by elimination, when you notice that "Orbit", "Period", and "Rotation" are not "Bodies".

jeka57 [31]3 years ago

6 0

Answer:

Central body

Explanation:

A P E X

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A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar

kakasveta [241]

Answer:

$W=4037.36\ J$

Explanation:

Given:

mass of ice melted, $m=3.3\times10^{-2}\ kg$

time taken by the ice to melt, $t=5\ min=300\ s$

latent heat of the ice, $L=3.34\times 10^5\ J$

Now the heat rejected by the Carnot engine:

$Q_R=m.L$

$Q_R=0.033\times 3.34\times 10^5$

$Q_R=11022\ J$

Since we have boiling water as hot reservoir so:

$T_H=373\ K$

The cold reservoir is ice, so:

$T_L=273\ K$

Now the efficiency:

$\eta=1-\frac{T_L}{T_H}$

$\eta=1-\frac{273}{373}$

$\eta=26.81\%$

Now form the law of energy conservation:

Heat supplied:

$Q_S-W=Q_R$

where:

$Q_S=$ heat supplied to the engine

$Q_S-\eta\times Q_S=Q_R$

$Q_S(1-\eta)=Q_R$

$Q_S=\frac{11022}{1-0.2681}$

$Q_S=15059.36\ J$

Now the work done:

$W=Q_S-Q_R$

$W=15059.36-11022$

$W=4037.36\ J$

8 0

3 years ago

A machine does 1000 J of output work when 2000 J of work is input. THe efficiency is

HACTEHA [7]

Efficiency = 1000/2000 = 0.5 = 50%

6 0

3 years ago

If you use a 40x objective to magnify a slide, the image you see through the eyepiece will be magnified how much times?

sammy [17]

4x time 10x (I think)

Here, this will help-
http://www.cas.miamioh.edu/mbiws/microscopes/Magnification.html#totalmagnification

8 0

3 years ago

for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th

mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

I is moment of inertia of the solid cylinder
α is angular acceleration of the cylinder
T is tension in the string
r is length of the string

α = Tr/I

$\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}$

where;

a is the downward acceleration of the solid cylinder
R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

7 0

2 years ago

A ball is tossed into the air from height of 8 feet with an initial velocity of 8 feet per second. find the time r(in seconds) i

-Dominant- [34]

For this case we have the following equation:
-16t + 8t + 8 = 0
The first thing we must do is rewrite the equation correctly.
We have then:
-16t ^ 2 + 8t + 8 = 0
Solving the polynomial we have:
t1 = -1/2
t2 = 1
We discard the negative root because we want to find the time.
Answer:
it takes for the object to reach the ground about:
t = 1 second

3 0

3 years ago