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finlep [7]
3 years ago
10

Which term describes the object that a satellite revolves around?

Physics
2 answers:
m_a_m_a [10]3 years ago
6 0

The object that a satellite revolves around is the <em>central body</em> of the system. <em>(C)</em>

For example:

-- The central body of the solar system is the Sun.

-- The central body for TV satellites, GPS satellites, weather satellites, and the International Space Station is the Earth.

-- The central body for Phobos and Deimos is Mars.

This should be a pretty easy question to answer by elimination, when you notice that "Orbit", "Period", and "Rotation" are not "Bodies".

jeka57 [31]3 years ago
6 0

Answer:

Central body

Explanation:

A P E X

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I think it’s going to be the 2nd one
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List down different layers of the sun. Rank these layers based on their distance from the sun’s center
vfiekz [6]

Answer:

Core

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Ranks of layers based on their distance from the sun’s center

1st-corona

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3rd-chromosphere

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3 years ago
What is the movement of a stationary object?
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If it is stationary, its not moving. there is no movement
8 0
4 years ago
A car with mass 950 kg and a speed of 16 m/s approaches an intersection. A 1300 kg minivan traveling at 21 m/s is heading for th
Alex73 [517]

Answer:

V_f = 13.8863 \angle 60.89\°

Explanation:

Our values are,

m_1 = 950Kg\\v_1 = 16m/s \\m_2 =1300Kg\\v_2 = 21m/s

We have all the values to apply the law of linear momentum, however, it is necessary to define the two lines in which the study will be carried out. Being an intersection the vehicle of mass m_1 approaches through the X axis, while the vehicle of mass m_2 approaches by the y axis. In the collision equation on the X axis, we despise the velocity of object 2, since it does not come in this direction.

m_1v_1=(m_1+m_2)v_fcos\theta

For the particular case on the Y axis, we do the same with the speed of object 1.

m_2v_2=(m_1+m_2)v_fsin\theta

By taking a final velocity as a component, we can obtain the angle between the two by relating the equations through the tangent

Tan\theta = \frac{m_2v_2}{m_1v_1}\\Tan\theta = \frac{1300*21}{950*16}\\\theta = tan^{-1}(1.7960)\\\theta = 60.89\°

Replacing in any of the two functions, given above, we will find the final speed after the collision,

(950)(16)=(950+1300)V_fcos(60.89)

V_f= \frac{(950)(16)}{(950+1300)cos(60.89)}

V_f = 13.8863 \angle 60.89\°

8 0
3 years ago
WHATS THE ANSWER HELP
cluponka [151]

Explanation:

I believe part of the question is missing. can you please check on it?

is there a part where the mass of the object is mentioned?

6 0
3 years ago
Read 2 more answers
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