Answer: 3 meters
Explanation:
If you were to use a 3 line answer then it would look like this:
d = W/F
d = 3000/1000
d = 3 meters
Answer:

Explanation:
According to the question
net force F = 2.20×10^6 N
displacement 
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19° ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S


Explanation :
Displacement refers to the distance between the final and the initial position. Hence the displacement of the ball will be the difference between the initial and the final displacement.
Let the initial position be 0.
Final position = 8 cm
So the difference between initial position and final position = 0 – 8 = - 8 cm.
So the billiard ball comes to rest 8.0 cm behind its orbital position.
Answer:
The maximum electric power output is 
Explanation:
From the question we are told that
The capacity of the hydroelectric plant is 
The level at which water is been released is 
The efficiency is
0.90
The electric power output is mathematically represented as
Where
is the potential energy at level h which is mathematically evaluated as

and
is the potential energy at ground level which is mathematically evaluated as


So
here 
where V is volume and
is density of water whose value is 
So

substituting values


The maximum possible electric power output is

substituting values


Answer:
The correct option is;
C. 1,715 m
Explanation:
We are given the information from the group of teen at the City edge
Time of arrival of explosion sound = 5 s after sighting
Time of sighting explosion = 5 s before hearing the boom
Speed of sound in air ≈ 343 m/s
Speed of light = 299,792 km/s
Therefore, distance covered by sound in 5 seconds is given by the following equation;


Hence Distance = 343 m/s × 5 s = 1715 m
To check, we compare the time it would take for the light to cover 1715 m
That is
which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.
Therefore, the distance of the students from the factory is approximately 1,715 m