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4vir4ik [10]
3 years ago
15

Question 1: A man trailing a trolley bag and suddenly, the wheels of the trolley bag get locked. The man realises that he has to

put extra effort to drag the bag. The man finds it difficult to drag the bag because
Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer: Because of the friction force acting directly on the bag.

Explanation:

The function of the wheels is diminish the effect of the friction force, when the friction pulls back, it makes the wheel rotate, and this force is not applied directly on the bag.

Now the wheels are not working, so now the friction is acting directly on the bag, this is why the mand finds more difficult to drag the bag.

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In a vertical dive, a peregrine falcon can accelerate at 0.6 times the free-fall acceleration g (that is, at 0.6 g ) in reaching
Andrei [34K]

Answer:2171.6 m

Explanation:

Given

Peregrine falcon dives in circular arc with radial acceleration of

a_r=0.6\cdot g

falcon achieves a velocity of v=113\ m/s

Radial acceleration is the acceleration towards the center and it depends upon speed and radius of arc

a_r=\frac{v^2}{r}

r=\frac{113^2}{0.6\times 9.8}

r=2171.59\ m    

6 0
3 years ago
A circular loop of wire with radius r=0.0250 m and resistance r=0.390 ohms is in a region of spatially uniform magnetic field. t
slavikrds [6]

Answer:

0.0133 A

Explanation:

The time at which B=1.33 T is given by  

1.33 = 0.38*t^3  

t = (1.33/0.38)^(1/3) = 1.52 s  

Using Faraday's Law, we have  

emf = - dΦ/dt = - A dB/dt = - A d/dt ( 0.380 t^3 )  

Area A = pi * r² = 3.141 *(0.025 *0.025) = 0.00196 m²

emf = - A*(3*0.38)*t^2  

thus, the emf at t=1.52 s is  

emf = - 0.00196*(3*0.38)*(1.52)^2 = -0.0052 V  

if the resistance is 0.390 ohms, then the current is given by  

I = V/R = 0.0052/0.390 = 0.0133 A

3 0
3 years ago
WILL MARK AS BRAINLIEST...,.. A constant force vector f =2i cap+3j cap-5k cap acts on a particle and displaces it from (1,2,-3)
Montano1993 [528]

Explanation:

Given that,

Force, F=2i+3j-5k

The particle displaces from (1,2,-3) m to (2,5,-1) m.

We need to find the work done by the force. Work done by the force is given by :

W = Fd

It is equal to the dot product of force and displacement.

Displacement from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) or (1, 3, 2) m

Work done,

W=F{\cdot} d\\\\W=(2i+3j-5k){\cdot} (i+3j+2k)

We know that, i.i=j.j=k.k=1

So,

W=1\ J

So, the work done by the force is 1 J.

6 0
4 years ago
Blank the constant velocity of a falling object when the force of air resistance is equal to the force of gravity
rewona [7]
The terminal velocity is the constant velocity of a falling object when air resistance and gravitational force cancel.
7 0
4 years ago
Một ắc quy cung cấp một dòng điện 6A liên tục trong 3 giờ thì phải nạp lại. Tính cường độ dòng điện mà ắc quy này có thể cung cấ
MAVERICK [17]

Answer:

I cannot read that language that u put so people might not be able to answer it

7 0
3 years ago
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