Ask question

Ask question

All categories

3 years ago

7

1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his mo

mentum as he leaves the jump?

2 answers:

Elenna [48]3 years ago

5 0

1350kgm/s

Explanation:

Given parameters:

Mass of Sam = 75kg

Velocity = 18m/s

Unknown:

Momentum = ?

Solution:

Momentum is the property of a moving body with respect to its mass and velocity.

Objects in motion have momentum. The more the velocity of a body, the more its momentum. Also, the more the mass of an object, the more momentum it possess.

Momentum is a function of the mass and the velocity of a body

Momentum = mass x velocity

Momentum = 75 x 18 = 1350kgm/s

learn more:

Conservation of momentum brainly.com/question/2990238

#learnwithBrainly

Olegator [25]3 years ago

5 0

Answer:

Momentum of sam as he leaves the jump is 1,350kgm

Explanation:

Momentum of a body is defined as the product of mass and velocity of a body.

Given mass of Sam = 75kg

Velocity = 18m/s

Momentum = mass × velocity

Momentum = 75kg × 18m/s

Momentum = 1,350kgm/s

You might be interested in

The resistance of 3A and 12V

liraira [26]

Resistance = V / I
= 12 / 3 = 4

6 0

2 years ago

Two students 8 meters apart are holding a stretched, coiled spring between them. One student sends a pulse down the string, and

IgorC [24]

Answer:

Explanation:

Distance travelled by wave = 8 x 2 = 16 m

Time taken = 4 s

velocity of pulse wave = distance / time

= 16 m / 4 s

= 4 m/s

8 0

3 years ago

What is the oldest animal on earth?

Lilit [14]

Answer:

e3f3ewfeewfewgwgewggegegeggegeggege

Explanation:

6 0

3 years ago

Read 2 more answers

A proton in a uniform electric field moves along a straight line with constant acceleration. Starting from rest it attains a vel

Sav [38]

a) The acceleration of the proton is $5.0\cdot 10^{13} m/s^2$

b) The time required to reach the given velocity is $2\cdot 10^{-8}s$

Explanation:

a)

This is a motion at constant acceleration, so we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the proton in this problem, we have:

$v=1,000,000 m/s$ is the final velocity

$u=0$ is the initial velocity (it starts from rest)

$s = 0.01 m$ is the distance covered

Solving for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{(1,000,000)^2-0}{2(0.01)}=5.0\cdot 10^{13} m/s^2$

b)

For this part, we can use the following suvat equation instead:

$v=u+at$

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken for the velocity to change from u to v

We have here the following data:

$v=1,000,000 m/s$ is the final velocity

$u=0$ is the initial velocity (it starts from rest)

$a=5.0\cdot 10^{13} m/s^2$

Solving for t, we find

$t=\frac{v-u}{a}=\frac{1,000,000}{5.0\cdot 10^{13}}=2\cdot 10^{-8}s$

Learn more about accelerated motion here:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0

3 years ago

PLZ HELP ME!!!!!!!!

mote1985 [20]

Answer:

1. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.77955 m

now frequency is given by

$f = \frac{343m/s}{ 0.77955m}$

f = 440 Hz

2. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.52028 m

now frequency is given by

$f = \frac{343m/s}{ 0.52028m}$

f = 659.3 Hz

3. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.65552 m

now frequency is given by

$f = \frac{343m/s}{ 0.65552m}$

f = 523.25 Hz

4. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 587.33 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{587.33}$

$\lambda = 0.584 m$

5. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 493.88 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{493.88}$

$\lambda = 0.6945 m$

6. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 698.46 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{698.46}$

$\lambda = 0.491 m$

7. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.5840 m

now frequency is given by

$f = \frac{343m/s}{0.5840m}$

f = 587.3 Hz

8. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.4375 m

now frequency is given by

$f = \frac{343m/s}{0.4375m}$

f = 784 Hz

9. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 783.99 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{783.99}$

$\lambda = 0.4375 m$

10. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 659.26 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{659.26}$

$\lambda = 0.520 m$

4 0

3 years ago

Read 2 more answers