Answer:
2.94g/L
Explanation:
First, let us derive an expression for the density, using the ideal gas equation:
PV = nRT (1)
V = nRT/ P (2)
Recall:
Number of mole(n) = mass(m)/Molar Mass (M)
n = m/M
Substituting the value of n into equation 2:
V = nRT/ P
V = mRT/ MP
Now Divide both side by m
V/m = RT/ MP
Inverting the above equation, we have:
m/V = MP/RT
But Density = m/V
Density = MP/RT
From the question given, we obtained the following data:
P = 2.3atm
T = 305K
Molar Mass of O2 = 16x2 = 32g/mol
R = 0.082atm.L/K /mol
Density = (32x2.3)/(0.082x305)
Density = 2.94g/L
Answer:
If carbon which has an electrongavity of 2.5 bonds with hydrogen, which has an electrongavity of 2.1, the bond between the two atoms will be classified as a(n) covalent bond → Totally TRUE
Explanation:
We must follow the Pauling's rules to solve these question.
The electonegativity of an element is defined as the ability it has to attract electrons that link it to another element. It is a periodic property, which allows predicting the polarity of the bond formed between two atoms, as well as its covalent or ionic character.
The Pauling scale values range from 0.7 for Francium (the least electronegative element) to 4 for Fluorine, the most electronegative. Using the electronegativities table we can predict the polarity of some compounds
ΔEn (C-H) = 2.5 - 2.1 = 0.4 → This is a covalent bond.
ΔEn ≤ 0.4 → Covalent non polar bond
0.5 < ΔEn < 1.7 → Covalent polar bond
ΔEn ≥ 1.7 → Ionic bond
Answer:
R = k[ A ]²
Explanation:
What we are being asked is to determine the exponents in the equation:
R = k [A ]^a [B]^b
where R = reaction rate of the chemical reaction, k is the reaction constant, [A ][B] are the concentrations, and a and b are exponents.
Now the reaction has b= 0 since changing the concentration of B has no effect on the rate.
So,
R = k [ A ]^a
Doubling the amount of A, quadruples the reaction. Therefore a= 2, and the best law equation is R = k[ A ]²
1 micro meter =
1 μm ^2 = 1 μm*1μm =
meters
1.5 μm^2 = 1.5 *
meters
μm^2 is a unit for surface. First you want to convert μm to meters which is unit for length and if you multiply units for length you get unit for surface.
