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Vesnalui [34]
3 years ago
8

Which contribution to society is scientific?

Chemistry
2 answers:
horrorfan [7]3 years ago
4 0
I believe that c is a contribution to society is scientific and that’s because all the other answers don’t really have anything to with science in general and a supernatural being is more of a belief thing well that’s what I think and well c is also mentioning like gravity and how it basically controls the solar system
Archy [21]3 years ago
3 0

Answer:

The correct answer is c.

Explanation:

The incessant advance of science and technology and their close link with social dynamics pose urgent challenges. Science has a fundamental role from which society as a whole benefit: it generates new knowledge, improves education and increases our quality of life. In the case of the understanding that gravity controls the solar system, it generates many benefits for society.

Have a nice day!

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For the reaction below , label each reactant as an electron pair acceptor or electron pair donor and as a Lewis acid or a Lewis
JulsSmile [24]

Since the reaction shown in the question is an acid - base reaction in the Lewis sense; the Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

<h3>What is  a Lewis acid?</h3>

A Lewis acid is a substance that accepts electron pair while a Lewis base donates an electron pair.

Now consider the given reaction; AlCl3 +Cl^- ------> AlCl 4 ^-. The Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

Learn more about acid - base reaction: brainly.com/question/14356798

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2 years ago
The amount of energy required to heat water for a 10-minute shower (50 gallons) is 2.2125 kJ. How many calories is this
Alenkinab [10]
First, we convert the given amount of energy into joules.
1 kJ = 1000 joules
2.2125 kJ = 2,212.5 Joules

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1 kilocalorie = 1000 calories

0.529 kilocalories = 529 calories
6 0
3 years ago
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. express the nu
bagirrra123 [75]
<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.

So the answer is:
8,12,48


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3 0
3 years ago
Read 2 more answers
20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as
shepuryov [24]

The reaction forms 98.76 g AlCl_3.  

We have the masses of two reactants, so this is a <em>limiting reactant problem</em>.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1. Gather all the information</em> in one place with molar masses above the formulas and everything else below them.  

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the <em>limiting reactant</em>  

Calculate the moles of AlCl_3 we can obtain from each reactant.  

<em>From Al</em>: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

<em>From Cl_2</em>: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

<em>Cl_2 is the limiting reactant</em> because it gives the smaller amount of AlCl_3.

<em>Step 4</em>. Calculate the <em>mass of AlCl_3</em>.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0
3 years ago
Given the two half-cell reactions for copper and iron below
liraira [26]

Answer:

No, i will not use a water pipe consisting of the two metals

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Looking at the reduction potential of the both metals, it is clear that an electrochemical cell is set up with iron as the anode and copper as the cathode.

This will make the iron to quickly corrode and eventually destroy the water pipe. It is better to have a set up in which another metal that is higher than iron in the electrochemical series is combined with it.

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