Answer:
answer in expl.
Explanation:
example of false solution.- Earth is not square
true eg. - we live in earth
The question is incomplete. Complete question is:
Which list represents the classification of the
elements nitrogen, neon, magnesium, and
silicon, respectively?
(1) metal, metalloid, nonmetal, noble gas
(2) nonmetal, noble gas, metal, metalloid
(3) nonmetal, metalloid, noble gas, metal
(4) noble gas, metal, metalloid, nonmetal
.................................................................................................................
Answer: The correct answer is option 2) nonmetal, noble gas, metal, metalloid
Reason:
1) Non-metal are bad conductors of electricity. Also non-metal are electronegative in nature. Hence, among the provided elements, nitrogen satisfied the criteria. Hence, it is a non-metal.
2) Noble gas are the elements which have completely filled outermost shell. Hence, among the provided elements, Neon satisfied the criteria.
3) Metal are good conductors of electricity. Also metal are electropositive in nature. Hence, among the provided elements, magnesium satisfied the criteria. Hence, it is a metal.
4) Metalloid have conductivity better than non-metals but poor than conductors. Hence, among the provided elements, Silicon satisfied the criteria. Hence, it is a metalloid.
Given- m= 1.75 g
Now moles of O2 gas= Mass/ Molar mass
n = 1.75/32
V= 2L
P= 1atm
R=0.0821.....Constant
As PV=nRT
=> T=PV/nR
= 1* 2/ (1.75/32)*0.0821 K
= 2*32/1.75* 0.0821 K
= 445.45 K
= (445.45- 273.15) degrees celsius
= 172.30 degrees celsius..... ANSWER
Answer: C₃H₈
Explanation:
From PV = nRT
Moles of CO2 = PV / RT =(1 x 1.037)/(0.08206 x ( 273+98.3)) = 0.0340 moles of CO2
CxHy + (x + (y/2))O₂ ----> xCO₂ + yH₂O
there is 1 mole of C in each mole of CO2 so moles of C in CO₂ = 0.0340 moles
mass of C in CO₂ = 0.0340 x 12 = 0.41 g
This means mass of C in the hydrocarbon = 0.41g
so mass of H in the hydrocarbon = 0.50 - 0.41= 0.09 g
moles of H in the hydrocarbon = mass/molar mass = 0.09/1 = 0.09 moles
molar ratio of C:H = 0.034 : 0.09 = 1 :2.67
or 3 :8
empirical formula is C3H8
