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lapo4ka [179]
4 years ago
5

The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Glucose-6-phosphate was mixed

with the enzyme under standard conditions and the reaction was allowed to come to equilibrium. If the Keq' is 0.50 and the equilibrium [glucose-6-phosphate] is 1.33 M, what is the equilibrium [fructose-6-phosphate]?
Chemistry
1 answer:
harkovskaia [24]4 years ago
5 0

Answer: the equilibrium is 0.667 M

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A energia térmica corresponde à soma das energias cinéticas associadas a todas as partículas que compõem um corpo. Essa afirmati
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A group of giraffes feeds on leaves and grasses during the daytime. Right now, it is dark out and the giraffes are not eating. I
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Carbon dioxide is moving out of the living things.

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Read 2 more answers
Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of
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<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

\Delta x.\Delta p=\frac{h}{2\pi}

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\Delta x = uncertainty in position = d = 4.50\times 10^{-5}m

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m = mass of oxygen molecule = 5.30\times 10^{-26}kg

h = Planck's constant = 6.627\times 10^{-34}kgm^2/s^2

Putting values in above equation, we get:

4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s

Hence, the uncertainty in the velocity of oxygen molecule is 4.424\times 10^{-5}m/s

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