Answer is in picture below.
Use 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; mass percentage of the chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; amount of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; amount of carbon.
n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.
This compound is dichlorocarbene CCl₂.
Answer:
Explanation:
To convert from grams to moles we must use the molar mass, which is found on the Periodic Table.
Use the molar mass as a ratio.
Multiply by the given number of grams: 118
Flip the fraction so the grams of argon will cancel each other out.
The original measurement of grams had 3 significant figures, so our answer must have 3 sig figs.
For the number we calculated, that is the hundredth place. The 7 in the thousandth place tells us to round the 5 to a 6.
There are about <u>2.96 moles of Argon</u> in 118 grams.
No the question is not balanced
Answer:
The answer to your question is below
Explanation:
Data
[HBr] = 0.045 M
[H⁺] = ?
[OH⁻] = ?
pH = ?
pOH = ?
Process
1.- Determine the [H⁺]
The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M
2.- Determine the pH
pH = -log[H⁺]
-Substitution
pH = -log[0.045]
-Result
pH = 1.35
3.- Determine the pOH
Formula
pH + pOH = 14
-Solve for pOH
pOH = 14 - pH
-Substitution
pOH = 14 - 1.35
-Result
pOH = 12.65
4.- Determine the [OH⁻]
pOH = -log[OH⁻]
-Solve for [OH⁻]
[OH⁻] = antilog(-pOH)
-Substitution
[OH⁻] = antilog (-12.65)
-Result
[OH⁻] = 2.22 x 10⁻¹³
Since mole ratio of magnesium to hydrochloric acid is 1:2, the answer is 1 mole of HCL.