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3 years ago

Sally has touched a hot pan on the stove and burnt her hand. This example shows what type of heat transfer?

Chemistry

1 answer:

Minchanka [31]3 years ago

6 0

Answer:

Transfer of Heat

You might have observed that a frying pan becomes hot when kept on a flame. It is because the heat passes from the flame to the utensil. When the pan is removed from the fire, it slowly cools down. Why does it cool down? The heat is transferred from the pan to the surroundings. So you can understand that in both cases, the heat flows from a hotter object to a colder object. In fact, in all cases heat flows from a hotter object to a colder object.

Explanation:

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If fahrenhite is 200 then what is the reading of celsius

sineoko [7]

Given Temperature=200°F

$\\ \bull\tt\longmapsto F=\dfrac{9}{5}C+32$

$\\ \bull\tt\longmapsto 200=\dfrac{9}{5}C+32$

$\\ \bull\tt\longmapsto \dfrac{9}{5}C=200-32$

$\\ \bull\tt\longmapsto \dfrac{9}{5}C=168$

$\\ \bull\tt\longmapsto C=\dfrac{5}{9}\times 168$

$\\ \bull\tt\longmapsto C=5(18.2)$

$\\ \bull\tt\longmapsto C=36.4°C$

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3 years ago

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what is the coordination number of cobalt in [co(nh3)5cl](no3)2? what is the coordination number of cobalt in [co(nh3)5cl](no3)2

rewona [7]

The coordination number of cobalt in the complex is 6.

What is coordination compound?

The number of ligands attach to the central metal atom or ion in coordination sphere is coordination number.

In given complex 5 NH3 and 1 chlorine is attached in coordination sphere, so coordination number is 6.

To know more about the coordination number please follow the link:

https://brainly.in/question/1115267

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1 year ago

Two atoms that are isotopes of one another must have a different number of what? protons neutrons electrons all particles 2 poin

Hatshy [7]

Neutrons, just took the test

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3 years ago

A newly discovered element, Z, has two naturally occurring isotopes. 90.3 percent of the sample is an isotope with a mass of 267

kirill115 [55]

Ok so, remember that t<span>he average atomic mass is what is seen on the periodic table. It is the average mass of all of the isotopes with their frequency taken into account. What you need to do is add the products of the masses and frequencies Just like this:</span>

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3 years ago

A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of

andrew-mc [135]

Answer: The molecular formula for the given organic compound X is $C_6H_{8}O_7$

Explanation:

We are given:

Mass of $CO_2=4.13g$

Mass of $H_2O=1.13g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, = $\frac{12}{44}\times 4.13=1.13g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, $\frac{2}{18}\times 1.13=0.125g$ of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = $\frac{0.094}{0.094}=1$

For Hydrogen = $\frac{0.125}{0.094}=1.33$

For Oxygen = $\frac{0.109}{0.094}=1.16$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is $C_6H_8O_7$

Empirical mass = $6\times 12+8\times 1+7\times 16=192g$

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

Putting values in above equation, we get:

$n=\frac{192g/mol}{192g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_6H_8O_7\times 1=C_6H_{8}O_7$

Thus molecular formula for the given organic compound X is $C_6H_{8}O_7$

7 0

3 years ago