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bagirrra123 [75]
3 years ago
10

When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because

Chemistry
2 answers:
Fantom [35]3 years ago
6 0

Answer: A

Explanation: i just took the test and quick answer

Oliga [24]3 years ago
4 0

Answer:

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Explanation:

  • The balanced equation of the reaction of hydrogen with nitrogen is:

<em>3H₂ + N₂ → 2NH₃</em>

it is clear that 3mol of hydrogen react with 1 mol of Nitrogen to give 2 mol of ammonia.

  • firstly, we need to calculate the number of moles of both

for H₂:

number of moles = mass / molar mass = (7.00 g) /  (2.00 g/mol) = 3.5 mol.

for N₂:

number of moles = mass / molar mass = (70.00 g) /  (28.00 g/mol) = 2.5 mol.

<u>using cross multiplication</u>

1 mol of  N₂ needs → 3 mol of H₂

2.5 mol of  N₂ needs → ??? mol of H₂

∴ the number of mol of H₂ needed = (3*2.5) / 1 = 7.5 mol

So, the right choice is:

7.5 mol of hydrogen would be needed to consume the available nitrogen.

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What factors could have affected your results?
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Answer:

See below  

Step-by-step explanation:

heat gained by metal + heat lost by water = 0

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Any factor that makes the numerator higher or the denominator lower than what you thought, will give a calculated C₁ that is too high (and vice versa).

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Factors Affecting the Calculation of Specific Heat Capacity

<u>          Too Low                 </u>              <u>      Too high                   </u>              

Water                                             Water

    Mass less than thought                Mass more than thought

    Ti lower                                         Ti higher

    T_f higher                                       T_f lower

Metal                                              Metal

    Mass more than thought             Mass less than thought

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