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choli [55]
3 years ago
5

Amy, Lee, Tom and Uma are candidates in the school election. The person

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

Tom/Lee

Step-by-step explanation:

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I am a three digit number. the sum of my digits is 26. my last two digits are the same. what number am i
Alex777 [14]
I think it is 989 or 899

*3 digit number*
*26 sum*
Last two digits are the same
6 0
4 years ago
What is the point slope equation of a line with slope -3 that contains the point (-8, -4)?
Lorico [155]

Answer:

y+4= -3(x+8)

Step-by-step explanation:

3 0
3 years ago
U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Pavel [41]

Answer:

The midpoint M is (5,7)

Step-by-step explanation:

m = ( \frac{x1 + x2}{2} , \frac{y1  + y2}{2} )

U(8,9)

V(2,5)

m = [(8+2)/2 , (9+5)/2]

= [(10/2) , (14/2)]

= (5,7)

(Correct me if i am wrong)

5 0
4 years ago
Analyze the diagram below and complete the instructions that follow. (7x - 3) (12x -7) Solve for x.
yarga [219]

Answer:

Step-by-step explanation:

(7x-3)(12x-7)

we are solving for x and we are multiplying.

we start with the x's 7x*12x=  84x

-3*-7=21

so now we have

84x+21=0

the 0 is a placer for answering the question

we minus 21 to both sides

84x=-21

now we divide

84/-21= -4

x=-4

6 0
2 years ago
What is the answer to:
velikii [3]
Weird way to write it but alright! (Sideways) 

19pq^-2 x 5pq^6 = ?

These problems are pretty much single operations between each of the variables / constants. 

So it's like this: 

(19*5)(p*p)(q^-2*q^6) = ?

19*5 is 95.

For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2. 

p*p is p^2

For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this: 

-2 + 6 = 4 
(The two is negative, because the power is negative 2) 

So, q^4. 

Our final answer is all of the combined.... like a so: 

95p^2q^4
3 0
3 years ago
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