If the separation between the plates of a parallel plate capacitor is doubled, then the energy stored in the capacitor also doubles
The work done in transferring charge from negative plate to the positive plate is stored as electrostatic energy in capacitor.
Consider a parallel plate capacitor of area A and d, the separation between two plates.
At any stage, the charge on the capacitor is Q
The total work done will be equal to Q²/2C
where C is the capacitance of the capacitor
This work done is stored as potential energy U,
∴ U = Q² / 2C
We know that the capacitance C of a parallel plate capacitor is equal to (ε₀ x A ) / d
Putting the relation of C in U we get,
U =
x Q² x [ d/ ( ε₀ x A ) ]
From this equation it is clear that energy store is directly proportional to the separation of the plates
∴ As separation between the plates is doubled, the electrical energy also get doubled.
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