Answer:
In constructive waves, a <u><em>greater</em></u> amplitude wave is formed. In destructive waves, a wave with a <u><em>smaller</em></u> amplitude is formed. (option A)
Explanation:
Interference is called the superposition or sum of two or more waves. Depending mainly on the wavelengths, amplitudes and the relative distance between them, there are two types of interference: constructive or destructive.
Constructive interference occurs when there are two waves of identical or similar frequency (both have motions equal to an even number of similar wavelengths) and overlap the peak of one with the peak of the other. These effects add together and make a wave of greater amplitude. All of this is possible because the waves were in the same phase in the beginning (in the same position).
Destructive interference occurs in the opposite case to constructive. When the crest of one wave overlaps the valley of the other, they cancel out since they are in different phases when they overlap (they were in different positions). That is, as in the case of constructive waves they were added, in the case of destructive waves they cancel out (subtract).
So, <u><em>In constructive waves, a greater amplitude wave is formed. In destructive waves, a wave with a smaller amplitude is formed. </em></u>
Force = mass x acceleration
force = 2500kg x (20m/s / 10m/s)
force = 2500kg x 2m/s^2
force = 5000kg m/s^2 = 5kN
i hope this is right (^^)
Answer:
Being an elastic object, rubber ball will be an ideal choice as it will bounce off the bowling pit and will experience a large change in momentum in comparison with the beanbag which will either slow down or come to a halt upon hitting a bowling pit. That is why rubber ball will experience a greater impulse and the bowling pin will experience the negative impulse of the rubber ball.
For Rubber Ball
Upon elastic collision it will reverses the direction and move with velocity equal or less then original
change in momentum = P
![P = m(v_{f} -v_{i})\\v_{f}=-v_{i} \\ P = -2mv_{i}](https://tex.z-dn.net/?f=P%20%3D%20m%28v_%7Bf%7D%20-v_%7Bi%7D%29%5C%5Cv_%7Bf%7D%3D-v_%7Bi%7D%20%5C%5C%20%20P%20%3D%20-2mv_%7Bi%7D)
For Beanbag
value of impulse will large if velocity is zero.
![v_{f}=0\\ P = -mv_{i}](https://tex.z-dn.net/?f=v_%7Bf%7D%3D0%5C%5C%20P%20%3D%20-mv_%7Bi%7D)
Explanation: