5 newton forward because the force of the engine is greater than the force of friction so that means the car is going forward.
You can think of this: when friction is greater than the force of an object its slowing down but when the force of the car is greater than the force of friction its speeding up.
Hope this helps
<h2>Answer: The more precisely you know the position of a particle, the less well you can know the momentum of the particle
</h2>
The Heisenberg uncertainty principle was enunciated in 1927. It postulates that the fact that each particle has a wave associated with it, imposes restrictions on the ability to determine <u>its position and speed at the same time. </u>
In other words:
<em>It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.</em>
<h2>So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity. </h2><h2 />
In fact, even with the most precise devices, the uncertainty in the measurement continues to exist. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.
Therefore the correct option is C.
The total force that the SUV exerts is:
F = 2000 kg * 3 m/s^2
F = 6000 N
Since a resisting force amounting to 1500 N is exerted,
then the force exerted by the SUV tires is:
F tire = 6000 N – 1500 N
F tire = 4500 N
L = illuminance
A = surface
i = intensity
L = i / A ==: i = L * A
i = 6 lux * 4 m^2 = 24 lumen
Answer:
a) B = 1.99 x 10⁻⁴ Tesla
b) B = 0.88 x 10⁻⁴ Tesla
Explanation:
According to Biot - Savart Law, the magnetic field due to a currnt carrying straight wire is given as:
B = μ₀ I L/4πr²
where,
μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹
I = current = 2 A
L = Length of wire = 40 cm = 0.4 m
a)
r = radius of magnetic field = 2 cm = 0.02 m
Therefore,
B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.02 m)²
<u>B = 1.99 x 10⁻⁴ Tesla</u>
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b)
r = radius of magnetic field = 3 cm = 0.03 m
Therefore,
B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.03 m)²
<u>B = 0.88 x 10⁻⁴ Tesla</u>
