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3 years ago

Consider a car turning about curved path of radius 40 m and banking angle 5 degree without skidding.

Physics

1 answer:

Fudgin [204]3 years ago

4 0

Explanation:

speed of curved path=under root of Mew and gravity

smooth surface Mew=0

so under root of 0×g

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Newton's law of cooling says that the rate of cooling of an object is proportional to the difference between the temperature of

Feliz [49]

Answer:

$T=T_o+C'e^{-kt}$

Explanation:

Newton's law of cooling

Rate of cooling

$\dfrac{dT}{dt}\alpha(T-T_o)$

Where To is the surrounding temperature

T is object temperature at any time t

now by removing proportionality sign

$\dfrac{dT}{dt}=-k(T-T_o)$

Now by separating variables

$\dfrac{dT}{(T-T_o)}=-k\ dt$

$\int \dfrac{dT}{(T-T_o)}=-\int k\ dt$

$\ln (T-T_o)=- k\ t +C$

Where C is constant

$T=T_o+C'e^{-kt}$

C' is also a constant and it can be find by using boundary conditions.

4 0

3 years ago

What is the average speed of a car that travels 40 mph for 1 hour and 60 mph in another hour?

svetoff [14.1K]

Average speed = (total distance covered) / (time to cover the distance)

-- Traveling at 40 mph for 1 hour, the distance covered is 40 miles.

-- Traveling at 60 mph for 1 hour, the distance covered is 60 miles.

-- Total distance covered = (40 miles) + (60 miles) = 100 miles

-- Total time = (1 hour) + (1 hour) = 2 hours

-- Average speed = (100 miles) / (2 hours)

<em>Average speed = 50 miles per hour</em>

6 0

3 years ago

What word describes the position in the moon's elliptical orbit when it is closest to Earth?

aivan3 [116]

That's the moon's perigee.

7 0

3 years ago

Marca las siguientes afirmaciones con V o F (verdadero o falso) y luego justifica aquellas que consideras falsas:

Harlamova29_29 [7]

Answer:

answer is

Explanation:

I need points

6 0

3 years ago

A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are added, the period becomes 33 sec. Assuming that

polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

$T=2\pi \sqrt{\frac{m}{k}}$ , here m is mass and k is spring constant

From the relation we can see that

$\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}$

$\frac{22}{33}=\sqrt{\frac{m}{m+22}}$

Squaring both side

$0.444={\frac{m}{m+22}}$

$0.444m+9.777=m$

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0

3 years ago