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3 years ago

Mass and weight are the same in meaning and unit. true or false

Physics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

False.

Explanation:

Mass is how much space an object takes up, while weight is how light or heavy an object is.

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If you exert a force on an object in motion you will change its what?

expeople1 [14]

You will change its <span>Velocity</span>

6 0

4 years ago

Read 2 more answers

Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o

Schach [20]

Explanation:

The given data is as follows.

Temperature of metal = $296^{o}C$ = (296 + 273) K

= 569 K

Density of the metal = 8.85 $g/cm^{3}$ = $8.85 \times 10^{-6} g/m^{3}$ (as $1 cm^{3} = 10^{-6} m^{3}$ )

Atomic mass = 51.40 g/mol

Vacancies = $9.19 \times 10^{23} m^{-3}$

Formula to calculate the number of atomic sites is as follows.

n = $\frac{\rho \times N_{A}}{\text{atomic weight}}$

= $\frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}$

= $1.036 \times 10^{17} atom/m^{3}$

Now, we will calculate the energy as follows.

E = $-KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})$

where, K = $8.62 \times 10^{-5}$

E = $-8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})$

= $78.46 eV/atom$

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is $78.46 eV/atom$ .

6 0

4 years ago

The circuit contains a filament bulb, connected with ........ to a ........

Katyanochek1 [597]

Answer:

The circuit contains a filament bulb, connected with terminal to a terminal.

Explanation:

The base of the electric bulb and the metal tip of the base are the two terminals of the bulb. One is called a positive terminal while the other is called a negative terminal. The filament of the electric bulb is connected to its terminals.

8 0

3 years ago

Copper wire is 1. 9 mm in diameter and carries a current of 20 a. What is the electric field stregnth inside this wire?

Tju [1.3M]

The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge.

The electric field strength is found as;

$\rm E = \frac{I \rho }{A} \\\\ \rm E = \frac{20 \times 1.68 \times 10^{-8} }{ (0.6385 \times 10^{-6}} \\\\ E= 0.5262 \ V/m$

Hence, the electric field strength will be 0.6252 V/m.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

#SPJ4

3 0

2 years ago

A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu

kolbaska11 [484]

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

$\omega f = \omega o-\alpha*t$

Solving for α:

$\alpha=\frac{\omega o-\omega f}{t}$

where ωo = 600*2*π/60; ωf = 0; t=10s

$\alpha=6.283rad/s^2$

The sum of torque is:

$\tau=I*\alpha$

$\tau=M*R^2/2*\alpha$

$\tau=0.060 N.m$

8 0

3 years ago