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11 months ago

Which equation represents the data shown in the table below?

Mathematics

1 answer:

spin [16.1K]11 months ago

8 0

Answer:

B. y = x +3

Step-by-step explanation:

The fastest way to find this answer is to substitute offered values of x and y into the given equations to see if they are true.

<h3>Substitution</h3>

Using the first line in the table, (x, y) = (2, 5), we have ...

A 5 = 2(2) . . . . false

B 5 = 2 +3 . . . . true

C 5 = 3(2) . . . . false

D 5 = 2 +1 . . . . false

<em>Additional comment</em>

Checking answer choices against the problem statement is one of many possible strategies for answering multiple-choice questions.

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Answer:

Step-by-step explanation:

$4^{n} = 16 \\\\4^{n} = 4^2\\\\$

n = 2

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n = -4

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A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats. How much scoops of oats are left in his bucket? Ent

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Step-by-step explanation:

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2 years ago

Solve the system of equation by the addition method x-2y=11 and -x+6y =-31

Sonbull [250]

Answer: x = 1, y = - 5

Step-by-step explanation:

The given system of linear equations is expressed as

x - 2y = 11- - - - - - - - - - - - -1

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- 2y + 6y = 11 - 31

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4y/4 = - 20/4

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Substituting y = - 5 into equation 1, it becomes

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3 years ago

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

$(x-2)\\ (x-3)\\ (x-5)$

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

$x=2\\ x=3\\ x=5$

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

$(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0$

therefore

the answer Part b) is

the cubic polynomial function is equal to

$x^{3}-10x^{2} +31x-30=0$

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2 years ago

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