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Igoryamba
2 years ago
9

In an electric current, the ___ particles flow or are pushed along a path

Chemistry
1 answer:
MakcuM [25]2 years ago
7 0
The negative particles flow or are pushed along a path
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What is a metal that forms two types of oxides and rusts in moisture​
monitta

Answer:

An example of a metal that rusts is Iron

6 0
3 years ago
Read 2 more answers
Which of the following is a diprotic acid? a. H2SO4 b. CH3COOH c. HC d. H3PO4
RUDIKE [14]

Answer:

The correct option is: A. H₂SO₄

Explanation:

Acid is a charged or a neutral molecule that is a proton donor and electron pair acceptors.

Acids can be classified into monoprotic acids and polyprotic acids.

Monoprotic acids are the acids that can release only one proton on dissociation.

Whereas, polyprotic acids are the acids that can release more than one proton on dissociation.

Diprotic acid is a type of polyprotic acid that can release two protons on dissociation. Example: H₂SO₄

4 0
4 years ago
7) Cooking or baking food results in a _________________ change
Flauer [41]
I think the answer is chemical change
6 0
4 years ago
A cupcake recipe designed to produce 18 cupcakes calls for 260 grams of
Vedmedyk [2.9K]

Answer:

317.7778 g

Explanation:

Given data:

Flour required for 18 cup cakes = 260 g

Flour required for 22 cup cakes = ?

Solution:

We will calculate the flour required for 1 cup cake.

260 g /18   = 14.4444 g

Fluor required for 22 cupcakes,

22× 14.4444 g = 317.7778 g

In short,

22 cupcake/18 cup cake×260 g = 317.7778 g

8 0
3 years ago
Consider the reaction:
Fofino [41]

The mass in grams of NH₃ produced from the reaction is 3.4 g

<h3>Balanced equation</h3>

We'll begin by writing the balanced equation for the reaction. This illustrated below:

N₂ + 3H₂ -> 2NH₃

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

<h3>How to determine the volume of NH₃ produced</h3>

From the balanced equation above,

1 dm³ of N₂ reacted to produced 2 dm³ NH₃

Therefore,

2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃

<h3>How to determine the mass of NH₃ produced</h3>

We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:

22.4 dm³ = 1 mole NH₃

Therefore,

4.48 dm³ = 4.48 / 22.4

4.48 dm³ = 0.2 mole of NH₃

Finally, we shall determine the mass of NH₃ as follow:

  • Molar mass of NH₃ = 17 g/mol
  • Mole of NH₃ = 0.2 mole
  • Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 0.2 × 17

Mass of NH₃ = 3.4 g

Learn more about stoichiometry:

brainly.com/question/13196642

#SPJ1

4 0
2 years ago
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