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Ilya [14]
3 years ago
7

10. How many g of Cu(OH)2 can be made from 9.1 x 1025 atoms of O?

Chemistry
1 answer:
il63 [147K]3 years ago
8 0
Molar mass Cu(OH)₂ = 97.561 g/mol

97.561 g Cu(OH)₂ --------------- 6.02x10²³ atoms
  ? g Cu(OH)₂ -------------------- 9.1x10²⁵ atoms

mass = 9.1x10²⁵ * 97.561 / 6.02x10²³

mass = 8.87x10²⁷ / 6.02x10²³

mass = 14734.2 g

hope this helps!
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Cells are organized into tissues. Tissues carry out specific functions. Groups of tissues can then form organs that also have specific functions to carry out. Lastly groups of organs form organ systems that regulate many functions in a specific part of the body.
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3 years ago
NaOH(aq) + MgSO4(aq) →
Cerrena [4.2K]

Answer:

if balanced reaction then 2 NaOH + MgSO4 → Mg(OH)2 + Na2SO4

Explanation:

3 0
3 years ago
Identify the compounds that are soluble in both water and hexane.
dlinn [17]

Answer:

The compound which are boh soluble in water and hexane is

B. Ethanol and 1-propanol  

Explanation:

The compounds ethanol and 1-propanol are soluble in both hexane and water.

It is soluble in water as both  consists of polar end due to hydrogen bonding present in the  -OH functional group.

and both are soluble in hexane as they contain a non polar end and the alliphatic hydrocarbon chain in them.

The solubility of alcohols varies in increasing order as the hydrocarbon chain increases. And becaue of this it becomes more non polar.

Non polar properties decreases for branched molecules.

so, the correct option is ethanol and 1-propanol.

3 0
3 years ago
Cu is in FCC structure. We know that even at close to melting temperature, vacancies are still sparsely distributed, i.e., it is
sveticcg [70]

Answer:

6

Explanation:

FCC is face centered cubic lattice. In FCC structure, there are eight atoms at the eight corner of the cubic unit cell and one atom centered in each of the faces. FCC unit cells consist of four atoms, (8/8) at the corners and (6/2) in the faces.

Given that, Cu has FCC structure and it contains a vacancy at origin (0, 0, 0). And there is no other vacancy directly adjacent to the vacancy at the origin. So, all the adjacent positions contain Cu atoms. Hence, the total number of adjacent atoms of the vacancy at origin can jump into this vacancy.

the above FCC unit cell clearly indicates that there are six adjacent atoms adjacent to the vacancy at origin

So, the total number of adjacent atoms of the vacancy at origin can jump into this vacancy is 6.

5 0
2 years ago
A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titra
Eddi Din [679]

Answer:

See explanation below

Explanation:

In order to calculate this, we need to use the following expression to get the concentration of the base:

MaVa = MbVb (1)

We already know the volume of NaOH used which is 13.4473 mL. We do not have the concentration of KHP, but we can use the moles. We have the mass of KHP which is 0.5053 g and the molecular formula. Let's calculate the molecular mass of KHP:

Atomic weights of the elements to be used:

K = 39.0983 g/mol;  H = 1.0078 g/mol;  C = 12.0107 g/mol;  O = 15.999 g/mol

MM KHP = (1.0078*5) + (39.0983) + (8*12.0107) + (4*15.999) = 204.2189 g/mol

Now, let's calculate the mole of KHP:

moles = 0.5053 / 204.2189 = 0.00247 moles

With the moles, we also know that:

n = M*V (2)

Replacing in (1):

n = MbVb

Now, solving for Mb:

Mb = n/Vb  (3)

Finally, replacing the data:

Mb = 0.00247 / (13.4473/1000)

Mb = 0.184 M

This would be the concentration of NaOH

8 0
3 years ago
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