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4 years ago

10. How many g of Cu(OH)2 can be made from 9.1 x 1025 atoms of O?

1 answer:

8 0

Molar mass Cu(OH)₂ = 97.561 g/mol

97.561 g Cu(OH)₂ --------------- 6.02x10²³ atoms
? g Cu(OH)₂ -------------------- 9.1x10²⁵ atoms

mass = 9.1x10²⁵ * 97.561 / 6.02x10²³

mass = 8.87x10²⁷ / 6.02x10²³

mass = 14734.2 g

hope this helps!

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Now putting all the values:

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3 years ago

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3 years ago

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4 years ago

Read 2 more answers

Which of the following is the correct set up AND answer to convert 6.25 x

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Answer:

Explanation:

How many mols do you have?

1 mol = 6.02 * 10^23 atoms

x mol = 6.25 * 10 ^32 atoms

1/x = 6.02*10^23 / 6.25 * 10^32 Cross multiply

6.02 * 10^23 * x = 1 * 6.25 * 10^32 Divide by 6.02 * 10^23

x = 6.25 * 10*32/ 6.02 ^10^23

x = 1.038 * 10^9 mols which is quite large.

Find the number of grams. (Use the value for copper on your periodic table. I will just use an approximate number.)\

1 mol of copper = 63 grams.

1.038 * 10^9 mols of copper = x

1/1.038 * 10^9 = 63/x Cross multiply

x = 1.038 * 10^9 * 63

x = 6.54 * 10^10 grams of copper.

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3 years ago