The answer would be <span>Tug Hill Plateau</span>
Answer:
0.01932 L
Explanation:
First we <u>convert 105 mM to M</u>:
Next we <u>convert 552 mL to L</u>:
Then we use the following equation:
Where:
We<u> input the given data</u>:
- 3 M * V₁ = 0.105 M * 0.552 L
And <u>solve for V₁</u>:
Answer:
Half life is 6 years.
Explanation:
T½ = In2 / λ
Where λ = decay constant.
But N = No * e^-λt
Where N = final mass after a certain period of time
No = initial mass
T = time
N = 0.625g
No = 10g
t = 24 years
N = No* e^-λt
N / No = e^-λt
λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)
λ = -(1 / 24) * In (0.625/10)
λ = -0.04167 * In(0.0625)
λ = -0.04167 * (-2.77)
λ = 0.1154
T½ = In2 / λ
T½ = 0.693 / 0.1154
T½ = 6.00 years.
The half life of radioactive cobalt-60 is 6 years
Answer:
the stem, but if its more specific xylem cells
The most common gas in the troposphere is nitrogen.
I hope this helps!
