Answer:
0.42 M
Explanation:
The reaction that takes place is:
- Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)
First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:
(200 mL = 0.200L)
- 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄
Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:
- 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂
Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:
- 0.224 mol - 0.14 mol = 0.085 mol
Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:
- 0.085 mol / 0.200 L = 0.42 M
it has an electrons in a fixed path together on energy levels.
[ H₃O⁺] = 10 ^- pH
[ H₃O⁺] = 10 ^ (- 5.75 )
[H₃O⁺] = 1.778x10⁻⁶ M
Kw = [ H₃O⁺] x [ OH⁻]
1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]
[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶
[OH⁻] = 5.62x10⁻⁹ M
hope this helps!
Answer
Depends on type of mixture. But I think separating the different sized particles through filtration would be a sufficient answer for middle school level unless they have taught you about other mixtures.
Explanation:
Hey,
There are thousands of way to separate mixtures. Each way is specific to the type of mixture. If the mixture is homogeneous processes like distillation can be employed. For heterogeneous mixture filtration can be used to separate particles of different sizes.
