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Bumek [7]
1 year ago
5

What does it mean to say an equation is balanced? Why is it important for an equation to be balanced?​

Chemistry
1 answer:
Rom4ik [11]1 year ago
8 0

Answer: It is important for an equation to be balanced because if it is not then the reactants won't match the products.

Explanation: I don't know if you will understand this but here:

Let's say you're cooking eggs, you're reactants so to speak would be 3 eggs and 1 tablespoon of oil so you put it together using heat and a pan. Your products have to match what you have in the beginning. You cannot have an equation that looks like this

Reactants = 3eggs + 1Tbsp oil ---pan/heat---> 6eggs + 1 cup of oil

You cannot get something from what you don't have. The number of how much of an element you have must be the same of both sides of the equation.

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Describe how the molecular structures of alkenes and alkynes differ from the structure of alkanes
evablogger [386]

Alkanes are saturated hydrocarbon that contains only single bonds, whereas Alkenes and Alkynes are unsaturated hydrocarbons which contain one or more double bond and triple bonds.

<u>Explanation:</u>

  • A saturated hydrocarbon with an only single bond is called alkanes. Ethane consisting of two carbon atoms that are bonded with a single bond and six hydrogen atoms sharing the other valence electron of carbon atoms. The molecular structure of alkane is CnH2n+2.
  • An unsaturated hydrocarbon with a two bond is called alkenes. Ethene consisting of two carbon atoms double-bonded to each other. The molecular structure of alkene is CnH2n.
  • An unsaturated hydrocarbon with a triple bond is called as alkynes. It involves sharing three pairs of electrons. The molecular structure of alkyne is CnH2n-2.
4 0
3 years ago
Which scientist established the law of octaves ?
goblinko [34]

the answer is D. John Newlands <3

5 0
3 years ago
Read 2 more answers
Determine the percent yield of a reaction that produces 28.65 g of Fe when 50.00 g of Fe2O3 react with excess Al according to th
Luba_88 [7]

Answer:

The percent yield of the reaction is 82%

Explanation:

First step: make the chemist equation.

2 Al (s) + Fe2O3 (s) → 2 Fe (s) + Al2O3 (s)

As the statement says that aluminun is in excess, the limiting reactant is the Fe2O3

Second step: Find out the moles in the reactant.

Molar weight Fe2O3: 159.7 g/m

Mass / Molar weight = moles

50 g /159.7 g/m = 0.313 moles

Third step: Analyse the reaction. 1 mol of Fe2O3 makes 2 moles of Fe.

1 mol Fe2O3 ____ 2Fe

0.313 mol Fe2O3 ____ 0.626 moles

Molar weight Fe = 55.85 g/m

Moles . molar weight = mass

55.85g/m . 0.626m = 34.9 grams

This will be the 100% yield of the reaction but we only made 28.65 g

34.9 g ____ 100%

28.65 g ____ 82.09 %

3 0
3 years ago
Read 2 more answers
Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th
shusha [124]

Answer:

See explanation below

Explanation:

The overall reaction, is:

MnO4⁻(aq) + H₂C₂O₄(aq) ---------> Mn²⁺(aq) + CO₂(g)

Balancing this redox reaction means that one compound is reducting while the other is oxidizing. So, we need to separate both compounds into 2 semi equations and balance both of them, per separate and then, we can join them.

As we want to balance in acid medium, means that we need to add water and H⁺ in both reactions. Doing that we have the following:

MnO₄⁻   ---------------> Mn²⁺

In this reaction, we can clearly see that it's not balanced. To balance this semi equation, let's see the elements. In the reactans we have Mn and O, but in the products we only have Mn, the atom of oxygen where could it be? As we are doing acid medium, if in the reactants we have oxygen, this oxygen can be as products in the form of water, so we add water there.

MnO₄⁻   ---------------> Mn²⁺ + H₂O

Now, the water has hydrogen atoms, and if we are in acid medium, the hydrogen can only come from the acid medium, and in this case H⁺ so:

H⁺ + MnO₄⁻ ----------> Mn²⁺ + H₂O

Now, it's time to balance the charges. First Mn²⁺ is the lowest oxidation state of the manganese, this means that in the reactants Mn is passing from a higher state to a lower state, therefore, this compouns is reducting. How many electrons? well, in this case, we know that oxygen usually have the oxidation state -2, so the manganese would be:

(-2 * 4) + x = -1

-8 + x = -1 -------> x = +7

Therefore, manganese passes from 7+ to 2+, it's gaining 5 electrons so:

H⁺ + MnO₄⁻ + 5e⁻ ----------> Mn²⁺ + H₂O

Finally, we just balance the masses and charges:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

Now, we just do the same thing with the other semi equation which is oxydizing. The explanation of that, is similar to this, so I'm gonna do it directly:

C₂O₄²⁻ -----------> CO₂

In this case, we can easily see that carbon is losing 2 electrons, so, let's put the 2 electrons on the product to balance the charges, and then, the masses:

C₂O₄²⁻ -----------> CO₂ + 2e⁻

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

Let's join both equations and do the sum of them:

8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O

C₂O₄²⁻ -----------> 2CO₂ + 2e⁻

As we can see, we do not have the same electrons on both equations, we need to equal those values so:

2 * (8H⁺ + MnO₄⁻ + 5e⁻----------> Mn²⁺ + 4H₂O)

5 * (C₂O₄²⁻ -----------> 2CO₂ + 2e⁻)

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

Now, let's sum both equations:

16H⁺ + 2MnO₄⁻ + 10e⁻----------> 2Mn²⁺ + 8H₂O

5C₂O₄²⁻ -----------> 10CO₂ + 10e⁻

___________________________________

16H⁺ + 2MnO₄⁻ + 5C₂O₄²⁻ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O

This would be the balanced reaction, however, let's put it as it was originally with the H2 in the C2O4 and balance it:

<h2>2MnO₄⁻ + 5H₂C₂O₄ + 6H⁺ -----------> 2Mn²⁺ + 10CO₂ + 8H₂O</h2>
7 0
3 years ago
If ahahah ahahahajja hajajiaja hajajwija hahaha jakakwkka ahsiwkwkkw
deff fn [24]

Answer:

20

Explanation:

no explanation cos no questions

8 0
3 years ago
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