The molar concentration of the original HF solution : 0.342 M
Further explanation
Given
31.2 ml of 0.200 M NaOH
18.2 ml of HF
Required
The molar concentration of HF
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)
Titrant = NaOH(1)
Titrate = HF(2)
Input the value :
Answer:
<h2>pH = 4.44 </h2>
Explanation:
The pH of a substance can be found by using the formula
![p H = - log[ H^{ + } ]](https://tex.z-dn.net/?f=p%20H%20%20%3D%20%20-%20%20%20log%5B%20H%5E%7B%20%2B%20%7D%20%20%5D)
where [ H+ ] is the hydrogen ion concentration of the solution
From the question
[ H + ] = 3.60 × 10^-5 M
So the pH is
We have the final answer as
<h3>pH = 4.44 </h3>
Hope this helps you
Answer:
Oxidation of potassium amalgam with carbon dioxide results in the formation of potassium oxalate. Potassium is not reactive with benzene, although heavier alkali metals such as cesium react to give organometallic products.
Please Mark Brainliest If This Helped!
The chemical reaction is expressed as:
2H2 + O2 = 2H2O
To determine the amount of oxygen used in the reaction, we use the amount of water produced and the relation of the substances in the reaction we do as follows:
209 g H2O ( 1 mol / 18.02 g ) ( 1 mol O2 / 2 mol H2O ) ( 32 g / 1 mol ) = 185.57 g O2
