The option which gives the correct mole ratios is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
<h3 /><h3>What is Mole ratio ?</h3>
It is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation
Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation
The balanced equation for given reaction is as follows ;
2H₂S + 3O₂ --> 2SO₂ + 2H₂O
Molar ratio can be determined by the coefficients of the compounds in the balanced reaction
Coefficient is the number in front of the chemical compound and they are as follows
- H₂S - 2
- O₂ - 3
- SO₂ - 2
- H₂O - 2
Therefore, correct option is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2
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Your answer is B. It gets energy from the Sun.
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Answer:
Water
Explanation:
Water is included as a compound!
Answer:
B. Ca2+ import into the ER because it has the steeper concentration gradient
Explanation:
ΔGt = RT㏑(C₂/C₁)
where ΔGt is the free energy change for transport; R = 8.315 J/mol; T = 298 K; C₂/C₁ is ratio of concentrations inside and outside each organelle.
For Ca²⁺ import
ΔGt = 8.315 J/mol * 298 K * ㏑(10⁻³/10⁻⁷)
ΔGt= 3.42 kJ/mol
For H⁺ import
ΔGt = 8.315 J/mol * 298 K * ㏑ (10⁻⁴/10⁻⁷)
ΔGt = 2.73 kJ/mol
From the above values, ΔGt is greater for Ca²⁺ import because it has a steeper concentration gradient
Answer:
3.94 L
Explanation:
From the question given above, the following data were obtained:
Mass of O₂ = 5.62 g
Volume of O₂ =?
Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:
Mass of O₂ = 5.62 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 5.62 / 32
Mole of O₂ = 0.176 mole
Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.
Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP
