Answer:
The temperature at 581.2 mL volume was 242.8 K.
Explanation:
Using Charle's law
Given ,
V₁ = 581.2 mL
V₂ = 830.5 mL
T₁ = ?
T₂ = 347 K
Using above equation as:
<u>The temperature at 581.2 mL volume was 242.8 K.</u>
Answer:
Q1: 1.67 L.
Q2: Saturated solution.
Explanation:
<u><em>Q1:</em></u>
- We have the role that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.
<em>(MV) before dilution = (MV) after dilution</em>
M before dilution = 10.0 M, V before dilution = 0.5 L.
M after dilution = 3.0 M, V after dilution = ??? L.
<em>∴ V after dilution = (MV) before dilution / M after dilution</em> = (10.0 M)(0.5 L) / (3.0 M) =<em> 1.67 L.</em>
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<u><em>Q2:</em></u>
From the given curve, it is clear that the solubility of sodium nitrate at 35.0°C is 100 g per 100 g of water.
<em>So, the mentioned solution is a saturated solution at this T.</em>
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<em>A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.</em>
Acid is an substance that ionized in water to produce hydrogen ion
Atom is the smallest neutral particle in the element
Covalent bond forms between the oxygen and hydrogen atoms.
(I attached a picture that could help)
-Hope that helps,
Good luck!
