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tiny-mole [99]
2 years ago
12

How would doubling the height of an object change the object's potential

Chemistry
1 answer:
atroni [7]2 years ago
5 0
B because since the height is being double the potential energy has twice the amount of space to explode
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Consider the balanced equation below.
kondaur [170]

The option which gives the correct mole ratios is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3 /><h3>What is Mole ratio ?</h3>

It is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

The balanced equation for given reaction is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

Molar ratio can be determined by the coefficients of the compounds in the balanced reaction

Coefficient is the number in front of the chemical compound and they are as follows

  • H₂S - 2
  • O₂ - 3
  • SO₂ - 2
  • H₂O - 2

Therefore, correct option is H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

Learn more about mole ratio here ;

https://brainly.in/question/32799056

#SPJ1

6 0
1 year ago
How does a tree get energy?
Snezhnost [94]
Your answer is B. It gets energy from the Sun.
Have a great day :)
6 0
2 years ago
Read 2 more answers
PLEASE PLEASE HELP ME
Sav [38]

Answer:

Water

Explanation:

Water is included as a compound!

5 0
2 years ago
[Ca2+] within the endoplasmic reticulum (ER) is 10-3M. Cytosolic [Ca2+] is 10-7M. Lysosomes in mammalian cells have an internal
Pani-rosa [81]

Answer:

B. Ca2+ import into the ER because it has the steeper concentration gradient

Explanation:

ΔGt =  RT㏑(C₂/C₁)

where ΔGt is the free energy change for transport; R = 8.315 J/mol; T = 298 K; C₂/C₁ is ratio of concentrations inside and outside each organelle.

For Ca²⁺ import

ΔGt = 8.315 J/mol * 298 K * ㏑(10⁻³/10⁻⁷)

ΔGt= 3.42 kJ/mol

For H⁺ import

ΔGt = 8.315 J/mol * 298 K * ㏑ (10⁻⁴/10⁻⁷)

ΔGt = 2.73 kJ/mol

From the above values, ΔGt is greater for Ca²⁺ import because it has a steeper concentration gradient

8 0
3 years ago
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

5 0
2 years ago
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