Molar mass of Benzoic Acid =122.1gmol −1 Morality of Ba(OH) 2=0.120mol/L2E6H5COOH+Ba(OH) 2→2H2+Ba(C6H5COO) 2 From the given Molar mass, we find the number of moles of Benzoic acid and Barium hydrocide. Moles of Benzoic acid = MolarMass GivenMass= 122.10.2=0.00163 Moles Moles of Ba(OH) 2= 20.00163=0.000815 Now, Morality of Ba(OH) 2= LitreofSolutionmolesofsolute=0.120M is required 1 Litre, So 0.000815M is required in 0.1201 ×0.000815 =0.00679=6.
