Question

Calculate the moles of benzoic acid (C6H5COOH) in a 55.66 g sample of benzoic acid

Answer 1

Molar mass of Benzoic Acid =122.1gmol
−1
Morality of Ba(OH)
2=0.120mol/L2E6H5COOH+Ba(OH) 2→2H2+Ba(C6​H5COO) 2
​From the given Molar mass, we find the number of moles of Benzoic acid and Barium
hydrocide.
Moles of Benzoic acid = MolarMass
GivenMass​= 122.10.2=0.00163 Moles
Moles of Ba(OH) 2= 20.00163=0.000815
Now, Morality of Ba(OH)
2= LitreofSolutionmolesofsolute=0.120M is required 1 Litre,
So 0.000815M is required in
0.1201 ×0.000815 =0.00679=6.