3 years ago

An objects momentum is determined by the object's

1 answer:

n200080 [17]3 years ago

7 0

~Hello there! ^_^

Your question: An objects momentum is determined by the object's..?

Your answer: An objects momentum is determined by the object's mass and velocity.

Happy Studying! =)

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When the space shuttle coasts in a circular orbit at constant speed about the earth, is it accelerating? if so, in what directio

pochemuha

Yes. Acceleration means any change in speed or direction of motion. When an object coasts in a circular orbit at constant speed around the Earth, its direction is constantly changing. The acceleration is "CENTRIPETAL", which points toward the center of the circle.

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3 years ago

Read 2 more answers

If the mass of an object i if the mass of an object is 44 kg in its velocity is 10 m/s East how much kinetic energy

vampirchik [111]

K=0.5 mu×u
K=2200J no matter the direction

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3 years ago

A vector starts at the point (0.0) and ends at (2,-7) what is the magnitude of the displacement

Leto [7]

Answer:

|x| = √53

Explanation:

We are told that the vector starts at the point (0.0) and ends at (2,-7) .

Thus, magnitude of displacement is;

|x| = √(((-7) - 0)² + (2 - 0)²)

|x| = √(49 + 4)

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2 years ago

An eastbound car travels a displacement of 80.0 Km in 45 minutes. What is the velocity

alexgriva [62]

Explanation:

d= 80km = 8000m

t = 45 min = 45/60 h

= 0.75 h

V= ?

we know that,

V = d /t

or,V= 80 km / 0.75 h

or, V= 106.67 km/hr

or,V= 106.67×1000m / 3600 s

2. or, V= 29.63 m/s

4 0

2 years ago

Suppose that the ultrasound source placed on the mother's abdomen produces sound at a frequency 2 MHz (a megahertz is 10^610 6

ella [17]

Answer:

the maximum frequency observed is 2.0044 10⁶ Hz

Explanation:

This is a Doppler effect exercise. Where the emitter is still and the receiver is mobile, therefore the expression that describes the process is

f ’= $f_o \ ( \frac{v \pm v_o}{v} )$

the + sign is used when the observer approaches the source

typical speeds of a baby's heart stop are around 200 m / min

let's reduce to SI units

v₀ = 200 m / min (1 min / 60 s) = 3.33 m / s

let's calculate

f ’= 2 10⁶ ( $\frac{1500 \ \pm 3.33}{1500}$ )

f ’= 2.0044 10⁶ Hz

f ’= 1,9956 10⁶ Hz

therefore the maximum frequency observed is 2.0044 10⁶ Hz

8 0

2 years ago