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Damm [24]
3 years ago
15

The motion of a car is represented as shown. The average

Physics
1 answer:
larisa86 [58]3 years ago
7 0

Average velocity :

  • \boxed{ \boxed{ \frac{displacement }{time} }}

  • \dfrac{20}{2}

  • 10 \: ms {}^{ - 1} East

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Which is a chemical reaction? Select one: a. a peanut shell cracking open into two halves b. solid chocolate melting into liquid
raketka [301]
My best educated guess would be d 
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3 years ago
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A proton is released in a uniform electric field, and it experiences an electric force of 5 X 10^-10 N toward the South. What is
Ymorist [56]

Answer:

Electric field on proton

E=3.12\times 10^9\ N/C

Explanation:

Given that

Force,F=5\times 10^{-10}\ N

We know that

Charge on proton

q=1.6\times 10^{-19}\ C

We know that

Force = Electric field x Charge

F= E x q

E=\dfrac{F}{q}\ N/C

E=\dfrac{5\times 10^{-10}}{1.6\times 10^{-19}}\ N/C

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Electric field on proton

E=3.12\times 10^9\ N/C

4 0
3 years ago
The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If
mart [117]

Answer:  29.50 m

Explanation: In order to calculate the higher accelation to stop a train  without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:

f=μ*N the friction force is equal to coefficient of static friction  multiply the normal force (m*g).

f=m.a=μ*N= m*a= μ*m*g= m*a

then

a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2

With this value we can determine the short distance to stop the train

as follows:

x= vo*t- (a/2)* t^2

Vf=0= vo-a*t then t=vo/a

Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m

5 0
3 years ago
What controls the traits an organism has?
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The Traits an organism displays are ultimately determined by the genes it inherited from its parents, in other words by its genotype. Variant copies of a gene are called alleles, and an individuals genotype is the sum of all the alleles inherited from the parents.

7 0
3 years ago
A string of 26 identical Christmas tree lights are connected in series to a 120 V source. The string dissipates 73 W. What is th
spin [16.1K]

To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,

R_{eq}= \frac{V}{I}

Here,

V = Voltage

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While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,

P=VI \rightarrow I = \frac{P}{V}

I =0.608 A

Applying Ohm's law

R_{eq} = \frac{120V}{0.608A}

R_{eq} = 197.4\Omega

Therefore the equivalent resistance of the light string is 197.4\Omega

6 0
3 years ago
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