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Contact [7]
3 years ago
6

Simplify x + 3x – 36.

Mathematics
2 answers:
Katena32 [7]3 years ago
5 0

Hey there!!

Equation Given : x + 3x - 36

In order to solve this, we will need to combine the like terms.

What are like terms?

Like terms are terms which have the same variable, in the equation given, the variable mentioned is x and hence, the like terms are x and 3x.

Now, we will need to combine x and 3x.

Let's take x as 1x and 3x as 3x.

Now, we will need to add both these like terms.

1x + 3x

x will be common, we will need to add 1 and 3

1 + 3 is 4 and hence, 1x + 3x = 4x

Hence, the final equation would be :

4x - 36

Hence, the answer is option ( c )

Hope my answer helps!

IRINA_888 [86]3 years ago
5 0

Answer:

4x-36 C

Step-by-step explanation:

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krok68 [10]

Answer:

See below.

Step-by-step explanation:

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9 ) 2.0

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3 years ago
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
3 years ago
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riadik2000 [5.3K]

Answer:

x = -1

Step-by-step explanation:

-1 + 3 = 2

-(-1) + 1 = 2 or 1 + 1 = 2

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