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FrozenT [24]
1 year ago
8

Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with wate

r and water with octanol when measuring ow?
Chemistry
1 answer:
notsponge [240]1 year ago
8 0

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by K_{OW} (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one,  when it's more dissolved in water, the value is lower.

What is the partition coefficient?

  • The partition coefficient for the two-phase network comprising n-octanol and water is known as the K_{OW} value. N-Octanol-Water Partition Ratio is another name for it.
  • The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by K_{OW}. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.
  • Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique K_{OW} ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

Learn more about octanol here:

brainly.com/question/7768749

#SPJ4

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Answer:

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6 0
3 years ago
If you were to describe the shape of the Milky Way, what term would you use? A. Irregular galaxy B. Elliptical galaxy C. Barred-
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C. Barred spiral galaxy
4 0
3 years ago
if the reaction occurs in the laboratory and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use
Helen [10]

The question is incomplete, here is the complete question:

The Haber process can be used to produce ammonia,  NH_3  and it is based on the following reaction.

N_2+3H_2\rightarrow 2NH_3

If the reaction occurs in the laboratory and 5 moles of each hydrogen and nitrogen gas reacts and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use the quantity of the product that is produced by the limiting reagent as the theoretical yield.

<u>Answer:</u> The percent yield of the reaction is 84.08 %.

<u>Explanation:</u>

We are given:

Moles of nitrogen gas = 5 mole

Moles of hydrogen gas = 5 mole

For the given chemical equation:

N_2+3H_2\rightarrow 2NH_3

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas

So, 5 mole of hydrogen gas will react with = \frac{1}{3}\times 5=1.67mol of nitrogen gas

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 5 moles of hydrogen gas will produce = \frac{2}{3}\times 5=3.33mol of ammonia

To calculate the percentage yield of ammonia, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of ammonia = 2.8 moles

Theoretical yield of ammonia = 3.33 moles

Putting values in above equation, we get:

\%\text{ yield of ammonia}=\frac{2.8mol}{3.33mol}\times 100\\\\\% \text{yield of ammonia}=84.08\%

Hence, the percent yield of the reaction is 84.08 %.

8 0
3 years ago
The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.
torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved  and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

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3 years ago
An atom's tendency is to become stable. What does this mean? A. The electrons all move to one electron shell. B. The atom gains
masya89 [10]
The answer is D. To put it simply, all atom wished to become stable. The only way for that is to obtain an octet structure where the outermost shell would have 8 electrons, thus being full.
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4 years ago
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