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FrozenT [24]
1 year ago
8

Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with wate

r and water with octanol when measuring ow?
Chemistry
1 answer:
notsponge [240]1 year ago
8 0

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by K_{OW} (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one,  when it's more dissolved in water, the value is lower.

What is the partition coefficient?

  • The partition coefficient for the two-phase network comprising n-octanol and water is known as the K_{OW} value. N-Octanol-Water Partition Ratio is another name for it.
  • The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by K_{OW}. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.
  • Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique K_{OW} ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

Learn more about octanol here:

brainly.com/question/7768749

#SPJ4

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A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the
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0.172 M

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The reaction for the first titration is:

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First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume</em>:

  • 19.6 mL * 0.189 M = 3.704 mmol HCl

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As for the second titration:

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We <u>determine how many NaOH moles reacted</u>:

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