Answer:
9.09cm3
Explanation:
The following data were obtained from the question:
Mass of dimethyl sulfoxide = 10g
Density of dimethyl sulfoxide = 1.10gcm−3
Volume of dimethyl sulfoxide =?
The density of a substance is simply the mass substance per unit volume of the substance. It is represented mathematically as:
Density = Mass/volume.
With the above formula, we can obtain the volume of dimethyl sulfoxide as follow:
Density = Mass/volume
1.10gcm−3 = 10g/ volume
Cross multiply to express in linear form
1.10gcm−3 x Volume = 10g
Divide both side by 1.10gcm−3
Volume = 10g / 1.10gcm−3
Volume = 9.09cm3
Therefore, the volume of dimethyl sulfoxide the student should pour out is 9.09cm3
Answer:
We need 1.714 moles N2
Explanation:
Step 1: Data given
The reaction yield = 87.5 %
Number of moles NH3 produced = 3.00 moles
Step 2: The balanced equation
N2(g)+ 3H2(g) →2NH3(g)
Step 3: Calculate moles N2
For 2 moles NH3 produced we need 1 mol N2 and 3 moles H2
This means, if the yield was 100%, for 3.00 moles NH3 produced , we need 1.5 moles N2
For a 87.5 % yield:
we need more N2, increased by a ratio of 100/87.5.
100/87.5 * 1.5 = 1.714 moles N2
Qwe4qdre4wrfwqe4rfwqerfwqerfq
Elements present in group 18 are known as noble gases. The outermost shell of these elements are completely filled.
18 is the answer
D water expands when it freezes
