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Allushta [10]
3 years ago
12

how much potassium bromide will form a saturated solution with 100 grams of water at 40 degrees celsius

Chemistry
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

75.4 g.

Explanation:

Hello there!

In this case, since the solubility stands for the maximum amount of a solute that is completely dissolved in a specific amount of solvent, typically 100 g of water as the universal solvent; we need to take into account that the higher the temperature the higher the solubility for the most of the solids.

In such a way, since the solubility of potassium bromide at 20 °C is 65.3 g per 100 g of water, at 40 °C is 75.4 g per 100 g of water, proving the aforesaid. Therefore, 75.4 g of potassium bromide will form a saturated solution with 100 g of water at 40 °C.

Regards!

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You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
What is the percent composition HCN?
kupik [55]

Answer:

see calculations in explanation

Explanation:

percent = part/total x 100%

part = ∑ atomic mass of element

  • hydrogen = 1.008 amu (atomic mass units)
  • carbon = 12.011 amu
  • nitrogen = 14.007 amu

total = ∑ molecular mass of compound

       = H amu  +  C amu +  Namu

       = 1.008 amu + 12.011 amu + 14.007 amu

       = 27.026 amu

%H = (1.008amu/27.026amu)100% = 3.730%

%C = (12.011amu/27.026amu)100% = 44.442%

%N = (14.007amu/27.026amu)100% = 51.827%

Check results ∑%values = 100%

3.730% + 44.442% + 51.827% = 99.999% ≅ 100%

7 0
3 years ago
If you dispense 40 ml of hexane, but it turns out you only need 5 ml, what should you do with the remainder?
Natasha2012 [34]

After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

<h3>Subtraction of Numbers</h3>

Given Data

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  • Volume needed = 5 ml

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

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Learn more about subtraction of numbers here:

brainly.com/question/4721701

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(although in reality, every bond is fundamentally the sharing of a pair of electron. but due to unmutal electonegativity, the molecule becomes polar)
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3 years ago
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