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Ierofanga [76]
2 years ago
13

238,2U --> 234Th + 90

Chemistry
1 answer:
stiv31 [10]2 years ago
5 0

Answer:

\\_{2}^{4} \alpha

Explanation:

In this question, we wish to find the missing nuclei for the equation:

\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X

In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:

238 = 234 + A

Notice from here that:

A = 238 - 234 = 4

So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:

92=90+Z

From here:

Z = 92-90=2

We have a particle:

\\_{2}^{4} X

Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:

\\_{2}^{4} \alpha

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