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Travka [436]
1 year ago
6

A 34.4 L sample of oxygen gas at 229°C and 752 torr is cooled to 34°C at 668 torr. The volume of the sample is now

Chemistry
1 answer:
kenny6666 [7]1 year ago
5 0

Answer:

23.55 L

Explanation:

USe the following 'identity' of gs laws

P1 V 1 / T1 = P2 V2 / T2         ( T must be in Kelvin)

re arrange to

P1 V 1  T2  /  (T1 P2)   = V2       NOW SUB IN THE VALUES

752 * 34.2 * ( 34 + 273.15) / [( 229 + 273.15) * 668]   = V2 = 23.55 L

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