The answer of the given question above would be option C. Based on the example of a Hertzsprung-Russell diagram that is shown, what can we say about white dwarfs is that, they are <span>relatively dim or faint, but very hot. Hope this answers your question. Have a great day ahead!</span>
6.941u? Sorry if I get it wrong
Answer:
The chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.
Explanation:
Chemical equation:
Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)
Balanced chemical equation:
Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)
This equation showed that the chlorine gas and potassium bromide solution react to form liquid bromine and potassium chloride solution.
Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.
The given equation is balanced and completely hold the law of conservation of mass.
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Answer:
5.82 ×10⁴ j
Explanation:
Given data:
Mass of water = 25.7 g
Amount of heat to evaporate it = ?
Molar heat of vaporization = 4.07×10⁴ j/mol
Solution:
First of all we will calculate the number of moles of water.
Number of moles = mass/ molar mass
Number of moles = 25.7 g/ 18 g/mol
Number of moles = 1.43 mol
Energy needed for one mole is 4.07×10⁴ j.
For 1.43 mol:
1.43 mol × 4.07×10⁴ j/ 1mol
5.82 ×10⁴ j
mass of pentane : = 30.303 g
moles of Al₂(CO₃)₃ : = 0.147
<h3>Further explanation</h3>
Given
1. Reaction
C₅H₁₂+8O₂→6H₂O+5CO₂.
45.3 g water
2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂
37.2 MgCO₃
Required
mass of pentane
moles of Al₂(CO₃)₃
Solution
1. mol water = 45.3 : 18 g/mol = 2.52
From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :
= 1/6 x mol H₂O
= 1/6 x 2.52
= 0.42
Mass pentane :
= mol x MW
= 0.42 x 72.15 g/mol
= 30.303 g
2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44
mol Al₂(CO₃)₃ :
= 1/3 x mol MgCO₃
= 1/3 x 0.44
= 0.147
