Answer:
Explanation:
The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.
First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.
Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).
Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.
Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.
NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.
There is two different types but i’ll just do both meanings just incase.
Graham's Law of Diffusion: the rate of diffusion of one gas through another is inversely proportional to the square root of the density of the gas.
Graham's Law of Effusion: the rate of effusion of a gas is inversely proportional to the square root of the density of the gas.
hopes this helps..!
Kinetic energy remains conserved in an elastic collision.
A because the end result of this reaction is a radical created by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol acts as the ring substituent in this situation.
<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
- The methyl group is transferred to cytosine in the first stage, and it is then hydroxylated in the second step.
- Therefore, a transferase and an oxidoreductase are the two groups of enzymes required.
<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
- Hydrogen bonding because the glucose's OH would form an H-bond with any exposed polar side chains on a protein surface.
<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH? </h3>
- Only positively charged proteins can bind to a cation-exchange column, and this can only happen when the pH is lower than the pI.
- Proteins A and B would both be positively charged at pH 7.0.
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Answer:
pH + pOH = 14, [H₃0⁺] [0H⁻] = 10⁻¹⁴
Explanation:
When it comes to questions involving pH, the equations used are;
[H₃0⁺] [0H⁻] = 10⁻¹⁴
This equation shows the concentration of hydroxonium ions alongside that of the hydroxide ions.
pH + pOH = 14
If the value of either the pH of the pOH is know,one can calculate the value of the other using this equation.
