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sertanlavr [38]
1 year ago
6

100 POINTS BRAINLIEST PICTURE BELOW

Chemistry
2 answers:
Paha777 [63]1 year ago
8 0

Answer:

D

Explanation:

Sparking can be caused by defective cooktop elements, loose connectors, a wire with frayed insulation or a broken wire arcing over to the appliance metal frame, says Appliance Repair. If the cause of the sparking is a broken wire or a wire with frayed insulation, do not attempt to splice the wire; you must replace it. Repair Clinic suggests checking the spark ignition switches, as they might be defective and in need of replacing.

ratelena [41]1 year ago
7 0

Answer:

B

Explanation:

Im pretty sure its B :,)

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Calculate the molality and van’t Hoff factor (i) for the following aqueous solutions:
MissTica

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of Van t Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

<h3>Which has highest Van t Hoff factor?</h3>

The Van't Hoff factor will be highest for

   A. Sodium chloride.

   B. Magnesium chloride.

   C. Sodium phosphate.

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1 year ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
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Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

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3 years ago
Phthalic acid has a solubility of approximately 18g per 100 ml of water at 100°c and 0.62g per 100 ml of water at 25°c. what is
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The minimum volume of water needed is 0.28 mL. The solution will have

1.7 mg of phthalic acid remaining in solution.

<em>At 100 °C</em>

Volume of water required = 50 mg HPh × (100 mL water/18 000 mg HPh)

= 0.28 mL water

<em>At 25 °C </em>

Mass of HPh in solution = 0.28 mL water × (620 mg HPh/100 mg water)

= 1.7 mg HPh

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An air mass is a huge body of air in the lower atmosphere that has similar temperature, humidity, and air pressure at given height

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When two different air masses come into contact together, they don't mix. Rather, they push against each other along a line called a front. When a warm air mass meets a cold air mass, the warm air rises since it is lighter. At high altitude it cools, and the water vapor it contains condenses.

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